Given that the complex number satisfies iz-1i = 1, find the minimum and maximum of iz-ii ∵|z-1|=1 On the complex plane, the corresponding point of Z is p (1,0) The center of a circle, a circle with a radius of 1 Connect the center P (1,0) and the point Q (0,1) Easy to know, | PQ | = √ 2 From the combination of number and shape, we can see that the meaning of | Z-I | is The distance from point to point Q (0,1) on circle p It can be obtained by combining number with shape |z-i|max=1+√2 |z-i|min=√2-1 But how can we get the center P (1,0) and point Q (0,1) in this step

Given that the complex number satisfies iz-1i = 1, find the minimum and maximum of iz-ii ∵|z-1|=1 On the complex plane, the corresponding point of Z is p (1,0) The center of a circle, a circle with a radius of 1 Connect the center P (1,0) and the point Q (0,1) Easy to know, | PQ | = √ 2 From the combination of number and shape, we can see that the meaning of | Z-I | is The distance from point to point Q (0,1) on circle p It can be obtained by combining number with shape |z-i|max=1+√2 |z-i|min=√2-1 But how can we get the center P (1,0) and point Q (0,1) in this step

This seems to be my answer

Given that the complex number Z satisfies | Z | = 1, then the minimum value of | Z + iz + 1 |, is___ ．

Let z = cosx + SiNx, | Z + iz + 1 | = [1 + 2cos (x + π 4)] 2 + 2sin2 (x + π 4) & nbsp; = 3 + 22cos (x + π 4) ≥ 3-22 = 2-1. When x3 π 4, the minimum value is 2-1. So the minimum value of | Z + iz + 1 | is 2-1

If Z satisfies iz = 2 + I, then z = a.2-i B. - 2 + I C.1 + 2I d.1-2i?
50 points····

Z=(2+i)/i=-i(2+i)=1-2i
Choose D