If x ∈ C, then the solution of the equation | x | = 1 + 3i-x is

If x ∈ C, then the solution of the equation | x | = 1 + 3i-x is


X = a + bi, a, B are real numbers
√(a^2+b^2)=1+3i-a-bi=(-a+1)+(-b+3)i
The left is real, so the right is real
So - B + 3 = 0
b=3
So √ (a ^ 2 + 9) = - A + 1
a^2+9=a^2-2a+1
a=-4
x=-4+3i