When a natural number is removed from 300262, the same remainder is obtained It's three numbers 300262205. Sorry!

When a natural number is removed from 300262, the same remainder is obtained It's three numbers 300262205. Sorry!

300-262=38
262-205=57
300-205=95
The greatest common divisor of 38 and 57,95 is 19, so this number is 19

Divide the natural number 300262205167 by a certain integer a, and the remainder is the same?

300÷1＝300…… 0
262÷1＝262…… 0
205÷1＝205…… 0
167÷1＝167…… 0
300÷19＝15…… fifteen
262÷19＝13…… fifteen
205÷19＝10…… fifteen
167÷19＝8…… fifteen
Happy learning!

When a number greater than 1 is removed from 300245210, the remainder is a, a + 2, a + 5. What is the natural number?

Analysis: do the analysis with the same transformation remainder and observe the remainder,
It is found that the remainder is more than 2 and 5,
When a number greater than 1 is removed from 300243205, the remainder is the same,
300-243=57=19×3
243-205=38=19×2,
So the natural number is 19

When a natural number greater than 1 is removed from 300245210, the remainder a, a + 2 and a + 5 are obtained respectively. What is the natural number?

The above problems can be described as follows:
300% x = a (here it is assumed that the% sign represents the remainder)
245%x=a+2
210%x=a+5
Then: 55% x = X-2
35%x=x-3
That is: 57% x = 0
38%x=0
X is the common divisor of 38 and 57. Since x > 1, x = 19