If 2A = 3B = 4C, then (a-b + C): (a + B-C)

If 2A = 3B = 4C, then (a-b + C): (a + B-C)


Let 2A = 3B = 4C = 12t, then a = 6T, B = 4T, C = 3T
Then the original formula = (6t-4t + 3T) / (6T + 4t-3t) = 5 / 7 (t can be reduced)



Given 2A + 3B + 4C = 5, find 2 ^ 2A 2 ^ 3B 2 ^ 4c-4
Let 2A + 3B + 4C = 5. Find the value of 2 ^ (2a) 2 ^ (3b) 2 ^ (4C) - 4


2^(2a)·2^(3b)·2^(4c)-4
＝2^(2a+3b+4c)-4
＝2^5-4
＝28.

Elden Ring Premiere

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