若2a=3b=4c,則(a-b+c):(a+b-c)的值

若2a=3b=4c,則(a-b+c):(a+b-c)的值


設2a=3b=4c=12t,則a=6t,b=4t,c=3t
則原式=(6t-4t+3t)/(6t+4t-3t)=5/7(t可以約去)



已知2a+3b+4c=5求2^2a 2^3b 2^4c-4
已知2a+3b+4c=5.求2^(2a)2^(3b)2^(4c)-4的值


2^(2a)·2^(3b)·2^(4c)-4
=2^(2a+3b+4c)-4
=2^5-4
=28.