On the quadratic equation AX2 + BX + C = 0 (a ≠ 0) of X, when a, B and C satisfy what conditions, the two equations are opposite to each other?

On the quadratic equation AX2 + BX + C = 0 (a ≠ 0) of X, when a, B and C satisfy what conditions, the two equations are opposite to each other?

Let two equations be X1 and X2, then X1 + x2 = - BA = 0, and the solution is b = 0, so AC ≤ 0. So when a, B and C satisfy B = 0, AC ≤ 0 and a ≠ 0, the two equations are opposite to each other

Definition: if the quadratic equation AX2 + BX + C = 0 (a ≠ 0) satisfies a + B + C = 0, then this equation is called "phoenix" equation. It is known that AX2 + BX + C = 0 (a ≠ 0) is "phoenix" equation and has two equal real roots, then the following conclusion is correct ()
A. a=cB. a=bC. b=cD. a=b=c

∵ the quadratic equation of one variable AX2 + BX + C = 0 (a ≠ 0) has two equal real roots, that is, a + B + C = 0, that is, B = - a-c, substituting b2-4ac = 0 to get (- A-C) 2-4ac = 0, that is, (a + C) 2-4ac = A2 + 2Ac + c2-4ac = a2-2ac + C2 = (A-C) 2 = 0, ∵ a = C

Write a linear equation of one variable with the following conditions: 1. The coefficient of the unknown is one half. If the solution of the equation is three, then the equation can be written as
Sorry, my wealth value is only 4 yuan, so I have no money for you. Sorry.

Too much can be written, such as 1 / 2x = 3 / 2, and 1 / 2x + a = B, as long as a and B satisfy B-A = 3 / 2!