As shown in the figure, draw the bisector OC of angle AOB with a protractor, take any point P in OC, and compare the distance from point P to OA and ob

As shown in the figure, draw the bisector OC of angle AOB with a protractor, take any point P in OC, and compare the distance from point P to OA and ob

Let the vertical lines from P to OA and ob intersect OA and ob at points E and f respectively
Because OC is the bisector of angle AOB
So angle EOP = angle fop
And because angle PEO = angle PFO = 90 degrees
So angle EPO = angle FPO
According to the principle of corner and corner,
Triangle EPO is equal to triangle FPO
So "PE = pf", that is, the distance from point P to OA, ob is equal

We usually use the following method to make bisector of known angle. Known: ∠ AOB (as shown in the figure). Find out the bisector of: ∠ AOB (1) Take 0 as the center of the circle, the appropriate length as the radius to make the arc, intersect 0A at m, intersect ob at n; (2) take M and N as the center of the circle, the length greater than 12mn as the radius to make the arc, and the two arcs intersect at point C inside ∠ AOB; (3) make the ray OC, which is the bisector of ∠ AOB. Please explain the reason why ray OC bisectors ∠ AOB with your mathematical knowledge

In △ OCM and △ OCN, OC = OCOM = onMC = NC, ≌ OCM ≌ OCN, ≌ MOC = ≌ NOC, that is, ray OC bisects ≌ AOB

Known: as shown in the figure, from point O is a point on the straight line AB, OC is the bisector of angle AOB, OD is in the angle cob
Teach me

Where is the picture

As shown in the figure, OC is the bisector of ∠ AOB, and ∠ AOD = 90 °. (1) the remaining angle of ∠ COD in the figure is______ (2) if ∠ cod = 24 ° 45 ', calculate the degree of ∠ BOD

(1) (2) AOC = AOD - cod = 90 ° - 24 ° 45 ′ = 65 ° 15 ′ (3 points) ∵ OC is the bisector of AOB, so AOB = 2 ∠ AOC = 130 ° 30 ′ (4 points) ∵ BOD = AOB - AOD = 130 ° 30 ′ - 90 ° 40 ° 30 ′. (5 points)

Is the bisector OC of ∠ AOB and this angle equal to 30?, which is the true proposition

Second

As shown in the figure, OC is the angular bisector of AOB, and M is any point on OC
As shown in the figure, the ray OC is the angular bisector of ∠ AOB, and the point m is on OC. ① draw a vertical line OA through point m, and the vertical foot is p; ② draw a vertical line ob through point m, and the vertical foot is Q; ③ measure the distance from point m to OA and ob, what do you find?

The distance from any point on the bisector to both sides of the corner is equal,

Given ∠ AOB = 2 ∠ AOC, is OC the bisector of ∠ AOB? Please draw a picture and explain it

As shown in the figure, C is not necessarily the bisector of AOB

Given ∠ AOB = 2 ∠ AOC, is OC necessarily the bisector of ∠ AOB?

Answer: not necessarily
OC may not be in the AOB

If OC is the bisector of angle AOB, then angle AOC=___ 2 angle AOC = 1 / 2___ Angle AOB = 2___

If OC is the bisector of angle AOB, then angle AOC = angle cob2, angle AOC = 1 / 2, angle AOB, angle AOB = 2aoc

It is known that the angle AOB is equal to 180, OC is any ray in the angle AOB, OC is the angular bisector of the angle AOC, OE is the angular bisector of the angle BOC
Proof: the angle DOE is equal to 90 degrees

Because od bisector AOC, OE bisector BOC
So angle AOD = angle cod = half angle AOC, angle COE = angle BOE = half angle BOC
Because the angle AOB is 180 degrees
So angle cod + angle COE = half angle AOB = half times 180 = 90 degrees
So angle DOE = angle cod + angle COE = 90 degrees
I'm tired of typing. I hope you can understand it=-=