Let a = (SiNx, 34), B = (13, 12cosx), and a ‖ B, then the acute angle X is______ ．

Let a = (SiNx, 34), B = (13, 12cosx), and a ‖ B, then the acute angle X is______ ．

∵ a ∥ B ∥ 12sinx & nbsp;; cosx = 14sin2x = 1 ∵ x is an acute angle ∥ x = π 4, so the answer is π 4

If vector a = (1-cosx, 1), vector b = (1 / 2,1 + SiNx), and vector a ‖ vector B, then the acute angle X is equal to

If two vectors are parallel, then the ratio of abscissa = the ratio of ordinate or one of them is a 0 vector. Obviously, neither of the two vectors in this problem is 0, so 2 (1-cosx) = 1 / (1 + SiNx) let SiNx cosx = t, then cosxsinx = (1-tt) / 2. From the above formula, t = 0 or 2 (rounding off), so t = 0, that is, x = 45 degrees, p.s.tt represents the square of T

It is known that x is an acute angle if SiNx

It is known that x is an acute angle if SiNx

X is an acute angle. Among the following values, SiNx + cosx may take the value of
a.3/4
b.4/3
c.5/3
c.1/2
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B. When x is an acute angle, the range of SiNx + cosx is from 1 to 2

SiNx * cosx = 60 / 169, X belongs to acute angle, find the value of cosx and SiNx

1 / 2sin2x = SiNx * cosx sin2x = 120 / 169... So 2x knows... So x knows... So cosx and SiNx know
No calculator. Excuse me-

X is the acute angle, find the maximum value of y = (1 + SiNx) (1 + cosx)

y=sinxcosx+sinx+cosx+1
Let a = SiNx + cosx = √ 2Sin (x + π / 4)
0

I know that the result of 1 / SiNx integral is ln|tanx / 2 |. The problem is to multiply cosx / 2 or SiNx / 2 after transforming it into 2sinx / 2 * cosx / 2
(here SiNx / 2 and cosx / 2 are obviously not zero) the re integration results are ln | TaNx / 2 | and LN | Cotx / 2 | respectively. Is there any problem with this method

First of all, the result is ln|tan (x / 2) | + C, not ln|tan (x / 2) | - --- note the brackets here, it's wrong not to add them
There is an arbitrary constant
And ln (Tan (x / 2)) = ln (sin (x / 2) / cos (x / 2)) = - ln (COS (x / 2) / sin (x / 2))
The absolute value is equal
So no problem

tanx=1/2,x=?tany=1/3,y=?

X is about 26 degrees 34 minutes
Y is about 18 degrees 26 minutes

Master into TaNx + tany / TaNx tany = 3 / 2 for TaNx / tany?

Let TaNx / tany = a ~ and then TaNx = a * tany ~ take it into the previous formula ~ (a + 1) tany / (A-1) tany = 3 / 2 (a + 1) / (A-1) = 3 / 2. Just calculate a directly. Ha ~ please calculate it yourself. Ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha ~ ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha! Ha

It is known that TaNx = 1 / 3, tany = - 2, and 0

tan(x+y)=(tanx+tany)/(1-tanx*tany)=(1/3-2)/(1-(1/3)*(-2))
=-1
Another 0