When solving the system of equations ax by = 13; cx-y = 4, student a got the solution x = 3, y = 2 because he misread the sign of B; student B got the solution x = 5, y = 1 because he missed C. try to find the value of a, B, C

When solving the system of equations ax by = 13; cx-y = 4, student a got the solution x = 3, y = 2 because he misread the sign of B; student B got the solution x = 5, y = 1 because he missed C. try to find the value of a, B, C

Ax by = 13; cx-y = 4, class a got the solution as x = 3, y = 2 because of the wrong sign of B. then, the system of equations becomes ax + by = 13cx-y = 4x = 3; y = 2 is replaced by 3A + 2B = 133c-2 = 4C = 2. Class B got the solution as x = 5, y = 1 because of missing C. then, the system of equations becomes ax by = 13x-y = 4x = 5, y = 1 is replaced by

Let a = {x | x ^ 2-8x + 15 = 0} and B = {x | AX-1 = 0}. If B is contained in a, find the set of real number a and write out all its nonempty proper subsets

A = {3,5} B = {1 / a} or when a = 0, B ∈ so the proper subset of a ∈ {1 / 3,1 / 5,0} has {1 / 3}, {1 / 5}, {0}, {1 / 3,0}, {1 / 3,1 / 5}, {1 / 5,0}. Thank you!

Let a = {x | X & sup2; = 4x = 0, X ∈ r}, B = {x | X & sup2; = 2 (a + 1) x + A & sup2; - 1 = 0, X ∈ r}, if B is a subset of a, find the value of real number a!
It's the content of the first year of high school
Let a = {x | X & sup2; + 4x = 0, X ∈ r}, B = {x | X & sup2; + 2 (a + 1) x + A & sup2; - 1 = 0, X ∈ r}, if B is a subset of a, find the value of real number a!

The solution of the equation x ^ 2 + 4x = 0 is x = 0 or x = - 4, so a = {x | x ^ 2 + 4x = 0} = {x | x = 0 or x = - 4} = {0, - 4} B = {x | x ^ 2 + 2 (a + 1) x + A ^ 2-1 = 0} requires B to be included in a, because the element of B is also the solution of a quadratic equation with one variable, so there are at most two elements in B. obviously, when the equation in B has two differences