If the point P (6-m, 2m-3) is in the fourth quadrant and the distance to the two coordinate axes is equal, then M =?

If the point P (6-m, 2m-3) is in the fourth quadrant and the distance to the two coordinate axes is equal, then M =?

P (6-m, 2m-3) is in the fourth quadrant
The results are as follows:
6-m>0
2m-3

If the known point P (2m + 3, 3m-1) is on the bisector of the angle between the first and third quadrant coordinate axes, then M=______ ．

∵ point P (2m + 3, 3m-1) is on the bisector of the first and third quadrants, ∵ 2m + 3 = 3m-1, the solution is m = 4, so the answer is 4

If the distance between the known point m (3m + 6, m-2) and the coordinate axis is equal, then M=

Do it in absolute terms
The distance from point m (3m + 6, m-2) to the coordinate axis is equal
Then the quadratic equation of one variable is obtained by moving the square of both sides of | 3M + 6 | = | m-2 |
m2+5m+4=0
The solution is m = - 1 or - 4