6√（3-4m）-3㎡√(3-4m)-8m√(3-4m)-9m+12㎡+2m^3=0

6√（3-4m）-3㎡√(3-4m)-8m√(3-4m)-9m+12㎡+2m^3=0

Let the root (3-4m) = x (x > 0 m)

Given M2 + m + 1 = 0, find the value of (3 M2 - 2m) - 2 (M2 - 3 / 2m) + 3

In the first step, remove the brackets from (3 M2 - 2m) - 2 (M2 - 3 / 2m) + 3 to get 3 M2 - 2m - 2 M2 + 3M + 3;
The second step is to merge 3 ^ - 2m-2 ^ + 3M + 3 into the same category to get ^ + m + 3;
In the third step, M2 + m + 3 = (M2 + m + 1) + 2;
The fourth step is to substitute M2 + m + 1 = 0 into the above formula, and get: (M2 + m + 1) + 2 = 0 + 2 = 2
A: the value of (3 M2 - 2m) - 2 (M2 - 3 / 2m) + 3 is 2

If M2 - 2m = 1, then the value of 2 M2 - 4m + 2007 is

2㎡-4m+2007
=2(㎡-2m)+2007
=2*1+2007
=2009

If M2 - 2m = 1, what is the value of 2 M2 - 4m + 2008
Please list the calculation process

m²-2m=1
If you multiply them by two, you get:
2m²-4m=2
therefore
2㎡-4m+2008
=2+2008
=2010