Simple calculation: (- 8) x (- 12) x (- 0.125) x (- one third) x (- 0.001)

Simple calculation: (- 8) x (- 12) x (- 0.125) x (- one third) x (- 0.001)

（-8）*（-12）*(-1/8)*-1/3*-1/1000=[(-8）*（-1/8 ]*[(-12) *-1 /3 ]*-1/1000=1*4*-1/1000=-1/250=-0.004

39 / 5 divided by 32x (5 / 1-8) + 18 / 5

39/5÷[32×(1-5/8)+18/5]
=39/5÷(32×3/8+18/5)
=39/5÷(12+18/5)
=39/5÷78/5
=36/5×5/78
=1/2

Simple calculation of 10.32 + 9.56-7.32 + 3.44

9.56+3.44+（10.32-7.32）

How to do 18 / 56 * 28 / 39 * 13

18/56*28/39*13
The results are as follows:
The original formula is 3

a. If B and C are rational numbers and the equation a + B √ 2 + C √ 3 = √ (5 + 2 √ 6) holds, then the value of 2A + 999b + 1001c is ()
(A) 1999 (b) 2000 (c) 2001 (d) uncertain

Because √ (5 + 2 √ 6) = √ (√ 2 + √ 3) 2 = √ 2 + √ 3
So a + B √ 2 + C √ 3 = √ 2 + 3, then a = 0, B = 1, C = 1
So 2A + 999b + 1001c = 0 + 999 + 1001 = 2000

A + √ 2B + √ 3C = √ (5 + 2 √ 6) find 2A + 999b + 1001c

√(5+2√6)=√(3+2√6+2)=√(√3+√2)^2=√3+√2
So:
a=0
b=c=1
2a+999b+1001c
=999+1001=2000

We know that a and B are rational numbers, and 3a-1 + 2b-5 = 0. Please find the value of a and B according to the definition of absolute value

Absolute values are all nonnegative
If the sum of two nonnegative numbers is 0, then both numbers are 0
3a-1=0
2b-5=0
The solution is as follows
a=1/3
b=5/2

Given that x is a rational number, does the algebraic formula X-1 + X-2 have a minimum value? What about the algebraic formula A-1 + A-2 + A-3 + A-4?
Are there any rules

X-1 + X-2 | denotes the sum of distances from point x to point 1 and point 2 on the x-axis. The minimum value is point 1 on the line segment of the two points=

It is known that there are three rational numbers a, B and C. when x = A / A + B / B + C / C, we can find the value of the algebraic formula 2x-1

When a, B and C are positive numbers, x = A / A + B / B + C / C = 3, then 2x-1 = 2 × 3-1 = 5; when a, B and C are negative numbers, x = A / A + B / B + C / C = - 3, then 2x-1 = 2 × (- 3) - 1 = - 7; when a, B and C have a negative number, then x = A / A + B / B + C / C = 1, then 2x-1 = 2 × 1-1 = 1

Given that a, B and C are rational numbers, | a | = 5, B2 = 9, (C-1) 2 = 4, AB > 0 and BC < 0, the value of AB BC CA is obtained

∵a | = 5, B2 = 9, (C-1) 2 = 4, ∵ a = ± 5, B = ± 3, C = - 1 or 3, ∵ AB > 0, BC < 0, ∵ a = 5, B = 3, C = - 1 or a = - 5, B = - 3, C = 3, ∵ original formula = 5 × 3-3 × (- 1) - (- 1) × 5 = 23 or original formula = (- 5) × (- 3) - (- 3) × 3-3 × (- 5) = 39