12 out of 7 to 3 out of 4

12 out of 7 to 3 out of 4

12 out of 7 to 3 out of 4 = 48:21 = 16:7

Simple calculation of 3.4/12.5
3.4 divided by 12.5

3.4/12.5=3.4x8/12.5x8=27.2/100=0.272

Simple mathematical calculation: 9 / 5 × 25% + 1 / 4 × 2.2-0.5

5% 9 × 25% + 4% 1 × 2.2-0.5
=0.25×1.8+0.25×2.2-0.25×2
=0.25×(1.8+2.2-2)
=0.25×2
=0.5
Do not understand can ask, help please adopt, thank you!

5 (3a-178; b-ab-178;) a (ab-178; + 3a-178; b), where a = 1 / 2, B = 1 / 3

5 (3a-178; b-ab-178;) - (ab-178; + 3a-178; b) where a = 189; b = 3 molecule 1

The result is reduced to the form (- 2A ^ - 2 × B ^ - 3) ^ - 3 × (AB ^ - 3) ^ - 2 with only positive integer exponential power

(-2a^-2×b^-3)^-3×(ab^-3)^-2
=-2^(-3)*a^6*b^9*a^-2*b^6
=-(a^4*b^15)/8

Mathematics problem (integer exponential power) 2
Given x + x ^ (- 1) = a,
Find x ^ 2 + x ^ (- 2) and x ^ 4 + x ^ (- 4)

x^2 + x^(－2)=(x+x^(-1))^2-2=a^2-2
x^4 +x^(－4)=(x^2+x^(-2))^2-2=(a^2-2)^2-2=a^4-2a^2+2

(integer exponential power)
Known p - P
X = 1 + 2, y = 1 + 2, where y is represented by X, the result is
2 an upper is to the power P and an upper is to the power (- P)

x=1+2^p
2^p=x-1
y=1+2^(-p)=1+1/2^p=1+1/(x-1)=x/(x-1)

The result is reduced to the form (a ^ - 3) ^ - 2 ^ [A & # 179; B · (a ^ - 1B) ^ - 2]

(a^-3)^-2÷[a³b·（a^-1b）^-2]
=a^6÷[a³b·（a^2b^-2）]
=a^6÷（a^5b^-1）
=a^6*(a^-5b)
=ab

(a ^ - 3) ^ - 2 △ [A & # 179; B · (a ^ - 1B) ^ - 2] is calculated and the result is reduced to the form containing only positive integer exponential power

The original formula = a ^ 6 ^ (A & # 179; b * A & # 178; / B & # 178;)
=a^6÷(a^5/b)
=a^6*1/a^5*b
=ab