1：4812-943+131 2：16.28+5.395-1.18-4.305

1：4812-943+131 2：16.28+5.395-1.18-4.305

1：4812-943+131=4812+131-943=4943-943=4000
2：16.28+5.395-1.18-4.305=(16.28-1.18)+(5.395-4.305)=5.1+1.09=6.19

1+(1/1+2)+(1/1+2+3)+...+(1/1+2+3+...100)=?

1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...100)
=1+1/3+1/6+1/10+...+1/5050
=2/2+2/6+2/12+2/20+...+2/10100
=2/(1×2)+2/(2×3)+2/(3×4)+2/(4×5)+...+2/(100×101)
=2(1/1-1/2)+2(1/2-1/3)+2(1/3-1/4)+2(1/4-1/5)+...+2(1/100-1/101)
=2(1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/100-1/101)
=2(1-1/101)
=200/101

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 +... + 100 + 99 + 98 +... + 3 + 2 + 1

Er. (1 + 100) * 50 * 2-100 = 10900

Factorization 4-x & # 178=

4-x²
=2²-x²
=(2 + x) (2-x) & nbsp; square difference formula
It's not easy. Thank you

Factorization m ^ 4-9n ^ 2

I'm glad to answer your question
m^4-9n^2
=(m^2+3n)(m^2-3n)

Factorization of m ^ 2-9n ^ 2
fast

（M+3N)(M-3N)

Factorization of m ^ 2x-9n ^ 2x-9n ^ 2 + m ^ 2Y

m^2x-9n^2x-9n^2y+m^2y
= m^2x+m^2y - (9n^2x+9n^2y )
= m^2 (x+y) - 9n^2 (x+y)
= (m^2 - 9n^2 ) (x+y)
= (m+3n ) (m-3n ) (x+y )

Decompose the following formats into factors: A & # 178; B & # 178; - M & # 178;, (M-A) &# 178; - (n + b) &# 178;, a & # 178; - 81,3
The following format is decomposed into the following format: a-a-\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\(x + y) & # 178; - (x + 2Y) & # 178;
Use square difference formula and complete square formula to solve other problems

(ab-m)(ab+m)
(m-a-n-b)(m-a+n+b)
(a-9)(a+9)
(6-x)(6+x)
(1-4b)(1+4b)
(m-3n)(m+3n)
m(m+2n)
(3a-11b)(11a-3b)
3(x-Y)(x+y)

How to factorize: 4m & # 178; - 9N & # 178; + H & # 178; - 4mh

4m²-9n²+h²-4mh
=（4m²-4mh+h²）-9n²
=(2m-h)²-9n²
=(2m-h+3n)(2m-h-3n)

The result of factoring M & # 178; - 9N & # 178; is

（m-3n）*（m+3n）