An isosceles trapezoid is formed by a 12.4 decimeter long iron wire. It is known that the two sides of the trapezoid are 6.4 decimeters long and the area is 9 square decimeters. What is the height of the trapezoid?

An isosceles trapezoid is formed by a 12.4 decimeter long iron wire. It is known that the two sides of the trapezoid are 6.4 decimeters long and the area is 9 square decimeters. What is the height of the trapezoid?

9 × 2 △ 12.4-6.4 = 18 △ 6 = 3 (decimeter) a: the height of trapezoid is 3 decimeter

An isosceles trapezoid is formed by a 12.4 decimeter long iron wire. It is known that the two sides of the trapezoid are 6.4 decimeters long and the area is 9 square decimeters. What is the height of the trapezoid?

9 × 2 △ 12.4-6.4 = 18 △ 6 = 3 (decimeter) a: the height of trapezoid is 3 decimeter

An isosceles trapezoid is formed by a 12. Decimeter iron wire. The two sides of the known trapezoid are 6.4 decimeters long and 9 square decimeters in area. How many decimeters is the height of the trapezoid?
solve equations

Solution: let the height of the trapezoid be h decimeter,
The total length of two isosceles trapezoid waist is 6.4 decimeters, then the waist length is 3.2 decimeters and 3.2 decimeters respectively,
Upper bottom + lower bottom = 12-6.4 = 5.6 decimeters,
Trapezoid area s = 5.6 * h * (1 / 2) = 9 h = 45 / 14 decimeters
If the angle between the waist and the bottom is α, then
sin α = h/3.2=225/224
Then you can work out how long the bottom is longer than the top, and then you can work it out
The data is troublesome. Is it wrong?

For any rational numbers a and B, it is stipulated that a ∧ B = A & # 178; - 2b, and the calculation is 3 ∧ - 2 and (- 5) ∧ - 1 & # 189;)

3※（-2）=3²-2×（-2）=9+4=13
（-5）※（-1½）=（-5）²-2×（-1½）=25+3=28
May I help you!

A, B are rational numbers and a, B satisfy (3 + 2 √ 3) a + (4 √ 3-2) B = 10-4 √ 3 to find the cube root of a & # 178;; B

(3+2√3)a+(4√3-2)b=10-4√3
(3a-2b)+(2v3a+4v3b)=10-4v3
3a-2b=10
2v3a+4v3b=-4v3
Solve the equation to get a, B
{a = 2,b = -2}
a^2=4
b^3=-8
Just bring it in

(1 / 11 + 1 / 33 + 1 / 55 + 1 / 77) is there a simple method?

(1/11+1/33+1/55+1/77)
=1/11x(1+1/3+1/5+1/7)
=1/11x(105/105+35/105+21/105+15/105)
=1/11x176/105
=16/105
If you don't understand this question, you can ask,

Simple calculation of primary school mathematics problems
4.15-3.75 * 10% - 5 / 8
1-39% * half / 0.195
Eleven fifths * 37% + sixty three percent / five fifths - two fifths

Question 1: 4.15-3.75 × 10% - 5 / 8
=4.15-0.375-0.625
=4.15-（0.375+0.625）
=4.15-1
=3.15
Question 2: 1-39% × half △ 0.195
=1-0.195÷0.195
=1-1
=0
Question 3: 11 / 5 × 37% + 63 / 100 △ 5 / 11 - 2 / 5
=11 / 5 × 31 / 100 + 63 / 100 × 11 / 5 - 2 / 5
=11 / 5 × (31 / 100 + 63 / 100) - 2 / 5
=Eleven fifths × 1 - two fifths
=Eleven fifths - two fifths
=Nine fifths

（3.14×20）/（3.14×0.5）

After simplification, 20 / 0.5 = 40

Can this problem be simplified?
1.5 * 8.4 + 3 * 3 / 10 + 15 * 1 / 10 fast!

1.5*8.4+3*3/10+15*1/10 =3*4.2+3*0.3+3*0.5 =3*(4.2+0.3+0.5) =3*5 =15

121121121121 121212121212
------------ * -------------
212121212121 212212212212
Do help me
That's a fraction. Don't take it as an integer

=(121121*1000001)/(212121*1000001)*(121212*100001)/(212212*1000001)
=121121/212121*121212/212212
=(121*101)/(21*10101)*(12*10101)/(212*101)
=(121)/(21)*(12)/(212)
=121*12/21/212
=121/7/53
=121/371