Given the radius and arc length, how to draw the arc with CAD

Given the radius and arc length, how to draw the arc with CAD

Method 1: first make a circle or arc from the known radius, then use the command of length, select T, input the length, and then select the segment to be cut off on the arc segment, leaving a fixed length arc
Method 2: first make a circle or arc from the known radius (if you draw a circle, you'd better cut off a section), and then use the measure command to divide equally. The set distance is the arc length you need. Pay attention to use the ddptype command to modify the style and size of the points, otherwise the points after the bisection can't be seen clearly
Method 3: calculate the angle, and then draw - arc - center, starting point, length (angle). But I personally don't like this method, recommend the first two methods. Finally, good luck!

Given chord length 12, height loss 1.8 and radius r = 11.672, calculate center angle, area and arc length

Given chord length L = 12, arc height h = 1.8, radius r = 11.672, calculate center angle a, area s, arc length C? R ^ 2 = (R-H) ^ 2 + (L / 2) ^ 2R ^ 2 = R ^ 2-2 * r * H + H ^ 2 + L ^ 2 / 42 * r * H = H ^ 2 + L ^ 2 / 4R = H / 2 + L ^ 2 / (8 * h) = 1.8 / 2 + 12 ^ 2 / (8 * 1.8) = 10.9A = 2 * arc sin ((L / 2) / R) = 2 * arc sin ((12 / 2) / 10.9)

It is known that the chord length of the bow is 11. The arc length is 12

Let R be the arc radius, then RN + 1 = (1 + (L-2 * RN * sin (C / (2 * RN))) / (L-C * cos (C / (2 * RN))) * rnrn + 1 = (1 + (11-2 * RN * sin (12 / (2 * RN))) / (11-12 * cos (12 / (2 * RN))))) * rnrn + 1 = (1 + (11-2 * RN * sin (6 / RN)) / (11-2 * RN * sin (6 / RN)) / (11