In order to welcome the national day, an environmental protection department of our city wants to inject the full wastewater from a rectangular waste water tank with a length of 2 × 10 ~ 3 DM, a width of 4 × 10 ~ 3 DM and a height of 8 × 10 ~ 2 DM into a cube water tank for purification, Can there be a cube storage tank to fill the waste water? If there is, find out the edge length of the cube storage tank. If not, explain the reason

In order to welcome the national day, an environmental protection department of our city wants to inject the full wastewater from a rectangular waste water tank with a length of 2 × 10 ~ 3 DM, a width of 4 × 10 ~ 3 DM and a height of 8 × 10 ~ 2 DM into a cube water tank for purification, Can there be a cube storage tank to fill the waste water? If there is, find out the edge length of the cube storage tank. If not, explain the reason

This is simple
Volume = L * w * h
Then the formula is as follows:
V=(2*10^3)*(4*10^2)*(8*10)
Put forward 10, that is
V=2*4*8*10^6
Since it is a cube, the cube with long edges is v
2*4*8=2^6
So the edge length is L = 400dm = 40m

When a 3-meter-long cuboid steel is formed into three sections, the surface area is increased by 2 mm, and the volume of this steel is () DM

Bottom length = 2 △ 2 = 1 square decimeter
3 meters = 30 decimeters
Volume = 1 × 30 = 30 cubic decimeter

The surface area of a cylindrical steel is 28.26 square decimeters. If its height is 1 / 2 of the bottom, what is the bottom area of the steel;
The surface area of a cylindrical steel is 28.26 square decimeters. If its height is 1 / 2 of the bottom, what is the bottom area of the cylindrical steel;

Assuming that the height is h and the radius of the bottom is r, we obtain that h = R / 2 cylinder surface area = side area + bottom area × 2 = 2 π RH + 2 π R & # 178; = 28.26 substitute H = R / 2 into 2 π RH + 2 π R & # 178; = 28.262 π R * (R / 2) + 2 π R & # 178; = π R & # 178; + 2 π R & # 178; = 3 π R & # 178; = 28.26 π R & # 178; = 9.42 bottom