Given that 1 / 4 + 5 (x-1 / 2004) = 1 / 2, find the value of algebraic formula 3 + 20 (x-1 / 2004)

Given that 1 / 4 + 5 (x-1 / 2004) = 1 / 2, find the value of algebraic formula 3 + 20 (x-1 / 2004)

1/4+5(X-1/2004)=1/2,
Multiply both sides by four,
1+20(X-1/2004)=2,
Two on both sides,
3+20(X-1/2004)=4

Why is one letter and one number an algebraic expression

1. Monomial: an algebraic expression that represents the product of a number and a letter. It is called a monomial. A single number or letter is also a monomial, such as, 2 π R, a, 0 A monomial is an algebraic expression in the form of the product of a number and a letter, that is, for a letter, it only contains multiplication

A single letter or number also becomes an algebraic expression

Where is the operation For example, a (letter) is a single letter (number) of 1 × A. --

According to the commutative law, we can get ()
A.b-a+c
B.-b+a+c
C.b-a-c
D.-b+a-c

C.b-a-c

46 students to travel A total of 18 ships were chartered Each ship can take six people The boat can take four people How many ships do you hire?

Wrong question! It belongs to the problem of chicken and rabbit in the same cage, which must be satisfied
Number of boats * number of boats

(x's square + X's Square) - 14 (x's square + x) + 24 = 0, solve the equation, cross multiplication, great gods help

(x + x) - 14 (x + x) + 24 = 0, that is, (x + X-2) (x + X-12) = 0 (x + 2) (x-1) (x + 4) (x-3) = 0, so x = 1 or 3 or - 2 or - 4

Factorization by cross phase multiplication: (square of X + 3) (square of X-2) - 14

(x^2+3)(x^2-2)-14
=x^4+x^2-6-14
=x^4+x^2-20
=(x^2-4)(x^2+5)
=(x+2)(x-2)(x^2+5)

Integral multiplication, if (2m + 2n-1) (2m + 2n + 1) = 63, find m + n

（2m+2n-1）（2m+2n+1）=63
[(2m+2n)-1]*[(2m+2n)+1]=63
(2m+2n)^2-1=63
(2m+2n)^2=64
2m + 2n = 8 or 2m + 2n = - 8
So m + n = 4 or - 4
Happy learning!

If m-2n = 4, then 4n-2m =, (m-2n) ^ 2-2n + m + 5=

4n-2m
=2(2n-m)
=-2(m-2n)
=-2x4
=-8
(m-2n)^2-2n+m+5
=(m-2n)^2+(m-2n)+5
=4^2+4+5
=16+4+5
=25

36 minus m plus 5 times of the sum of n minus m and the square of the sum of N decomposes the factor by cross multiplication

36 minus m plus five times the sum of n minus the square of the sum of M and n
36-5(m+n)-(m+n)²
=(9+m+n)(4-m-n)