If the quadratic y of 4x and the m-th power of - 2x and the n-th power of Y are of the same kind, then M-N =? Look at the title

If the quadratic y of 4x and the m-th power of - 2x and the n-th power of Y are of the same kind, then M-N =? Look at the title

If the second power y of 4x and the m power y of - 2x are of the same kind
Then 2 = m, 1 = n
So M-N = 2-1 = 1

Mathematics problem of grade one in junior high school: if 5x & # 178; + mx-y and 3x & # 178; + y have the same number of terms, then M is ()
If 5x & # 178; + mx-y and 3x & # 178; + y have the same number of terms, then M is ()
A.0 B.1 C.3 D.-5

3x & # 178; + y has two terms
So if 5x & # 178; + mx-y is also 2 terms, then M = 0

If the degree of the monomial negative two-thirds a to the nth power B is 5, find the value of n

n+2=5
n=5-2
n=3

If the n power of 5 multiplied by the N + 1 power of X multiplied by the n power of YZ is a binomial of degree 8, then the value of n is ()
n n+1 n
If 5 x YZ is a binomial of degree eight, then the value of n is ()
A. 7 / 3
B. 7 / 2
C.2
D.3
The upper N.N + 1. N is the power of the lower number to be brought in, they are a whole

5^n*x^(n+1)*(yz)^n
=5^n*x^(n+1)*y^n*z^n
5 ^ n is a constant and is not included in the degree of the monomial
So the order of this monomial is (n + 1) + N + n = 8
3n+1=8
n=7/3
Choose a

It is known that the sum of the times of monomials (- 3a to the power of M + 2) and (2x to the power of 7 × y to the power of N + 1) is 18. Find the values of positive integers m and n

It is known that the sum of the times of the monomials (- M + 2 power of 3a) and (7 power of 2x × n + 1 power of Y) is 18
m+2+7+n+1=18
m+n=8
The values of positive integers m and N are
m=1 n=7
m=2 n=6
m=3 n=5
m=4 n=4
m=5 n=3
m=6 n=2
m=7 n=1

If the degree of M minus 4 of the square B of the binomial 3a is the same as that of the cubic YZ of the 1 / 3 x of the binomial 3a, find the absolute value of m plus m minus 1

Because the number of 3 A ^ 2 B ^ (M-4) is the same as that of (1 / 3) x ^ 3 YZ,
The results are as follows: 2 + (M-4) = 3 + 1 + 1,
The solution is m = 7,
Therefore, m ^ 2 + | M-1 | = 55

Why can't the three forces of 2n, 3N and 6N acting on the same object at the same time make the object move at a uniform speed? Why can't the three forces of 3N, 4N and 5N move at the same time
Can we make the object move in a straight line at a uniform speed?

Because the resultant force of 2n, 3N and 6N acting on the same object at the same time can not be zero, so the object can not move at a constant speed. The reason is that 2n and 3N combine 5N at most, while 5N is less than 6N. Because the resultant force of 3N, 4N and 5N acting on the same object at the same time can be zero, so the object can move at a constant speed

The two forces acting on the same object are 6N and 8N respectively, and the resultant force may be ()
A. 1NB. 3NC. 13D. 15N

Two forces acting on an object, F1 = 6N, F2 = 8N, when the direction of the two forces is opposite, the resultant force is the smallest: F = f2-f1 = 8n-6n = 2n, when the direction of the two forces is the same, the resultant force is the largest: F = F1 + F2 = 8N + 6N = 14N, because the direction of the two forces is uncertain, so the resultant force may be equal to 2n, also

At the same time, the two opposite forces acting on an object are 6N and 8N, respectively. When the 8N force gradually decreases to zero, the resultant force of the two forces is ()
A. First decrease, then increase B. first increase, then decrease C. gradually increase D. gradually decrease

Because the directions of the two forces are opposite, the resultant force is equal to the difference between the two forces, that is, fhe = F1-F2 = 8n-6n = 2n, when F1 decreases gradually, the resultant force decreases, when F1 = 6N, the resultant force is zero; when F1 continues to decrease, fhe = f2-f1, the resultant force will gradually increase; therefore, the resultant force of the two forces first decreases and then increases; therefore, a

3m+2n/4=m+5n/-3=m-3n/5

From 3m + 2n / 4 = m + 5N / - 3 = m-3n / 5, we know: 3M + 2n / 4 = m + 5N / - 3 equation 1 4m + 20n = - 9m-6n13m + 26n = 0m + 2n = 0m = - 2n 3M + 2n / 4 = m-3n / 5 equation 2 4m-12n = 15m + 10n11m + 22n = 0 m = - 2n m + 5N / - 3 = m-3n / 5 equation 3 5m + 25N = - 3M + 9n8m + 16N = 0m = - 2n, that is, the solution is m-2n