If ma2 − b2-2ab − b2a2 − B2 = a − Ba + B, then M=______ ．

If ma2 − b2-2ab − b2a2 − B2 = a − Ba + B, then M=______ ．

It is known that m − 2Ab + b2a2 − B2 = a − Ba + B = (a − b) 2A2 − B2, m-2ab + B2 = (a-b) 2, M = A2

If M and N are opposite to each other, then M + N-5 = () m + n-2-2m-2n=
The first question I figured out - 5. The second question -

m. N is opposite to each other, M + n = 0
m+n-2-2m-2n=m+n-2-2(m+n)=0-2-0=-2
-2m-2n = - (2m + 2n) = - 2 (M + n) = - 2 * 0 = 0, understand?

If M + 1 / 3 and 2m-3 / 3 are opposite to each other, find M

∵m+1/3+2m-3/3=0
∴m+1+2m-3/3=0
∴3m-2=0
∴m=2/3

m. N is opposite to each other, find 2m + 2n + 2-m + 3 / n
Seeking 3 / 2m + 2n + 2 - (M + n)

M n is opposite to each other
m+n=0
2m+2n+2-（m+n）=3/[2（m+n）+2-（m+n）]=3/2

Calculation or simplification: (1) 8-2sin45 ° + (2 - π) 0 - (13) - 1 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; (2) A2 − 9A2 + 6A + 9 (1-3a)

(1) The original formula = 22-2 × 22 + 1-3 = 22-2-2 = 2-2; (2) the original formula = (a + 3) (a − 3) (a + 3) 2 × AA − 3 = a − 3A + 3 × AA − 3 = AA + 3

A-1 / A + 2 * A2-4 / a2-2a + 1 △ 1 / A2-1, where a2-a = 0
1, first simplify and then evaluate: A-1 / A + 2 * A2-4 / a2-2a + 1 △ 1 / A2-1, where a2-a = 02, (x2-3x / x2-1) + (2x-1 / x-1) = 0

1.a²-a=0,a=0,1
(a-1)/(a+2)*(a²-4)/(a²-2a+1)÷1/(a²-1)=(a-1)/(a+2)*(a-2)(a+2)/(a-1)²÷1/[(a-1)(a+1)]=(a-1)(a-2)(a+1)
A = 0, the original formula = - 2,
A = 1, the original formula = 0
2. The original formula = (X & sup2; - 3x) / (X & sup2; - 1) + (2x-1) (x + 1) / (x-1) (x + 1)

(the third power of 3A - the second power of 2A + 5A + 7) + (- the second power of 2A - half a + 3) - (- the third power of 4A + the second power of half a + 6a-5)

The second party of-2a + 5A + 7 + 5A + 7) + (the second party of-2a-one-half a + 3) - (the third party of-4a + the second party of one-half a and the second party of-2a + 5A + 5A + the second party of-2a + 5A + 5A + the second party of-2a + 5A + the second party of-2a + 5A + the second party of-2a + 5a-one-half a a + 3 - (the third party of-4a + the second party of-one-half a + 3A + the second-half a + 3A + the second-half a + 3A + the second-half a + the second-half a-half a + 3-2a + the second-half of the second-a-2a-2a-a + 2a-a-a-a-2a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-2 + 5

The square of 5a-6a + the square of 9A = the square of 5a-3 ()

The square of 5a-6a + the square of 9A = the square of 5a-3 (the square of 2a-3a)

(- 3 / 5A to the third power and B to the fourth power) divided by (1 / 5ab to the square)

Hello!
The beauty of Mathematics
3 1
( - —— a³ b⁴ ) ÷ ( —— a b² )
5 5
3 5
= －—— a³ b⁴ × ———
5 a b²
= －3 a² b²

If the second power of a - 3B + 1 = 0, try to find the algebraic formula (the fifth power of 2A - the fourth power of 5A + the third power of 2A - the second power of 8a) divided by (the square of a + 1)

(quintic power of 2A - quartic power of 5A + cubic power of 2A - quadratic power of 8a) divided by (square of a + 1)
=[2A^3(A^2+1)-5A^2(A^2+1)-3(A^2+1)+3]/(A^2+1)
=2A^3-5A^2-3+3/(A^2+1)
=2A^3-2A^2-9B+1/B