(x-4) square-21 = 6x is changed into the general form, where the coefficient of the second term is; the coefficient of the first term is; the constant term is; the coefficient of the second term is; the coefficient of the first term is;

(x-4) square-21 = 6x is changed into the general form, where the coefficient of the second term is; the coefficient of the first term is; the constant term is; the coefficient of the second term is; the coefficient of the first term is;

(x-4)²-21=6X
x²-8x+16-21-6x=0
x²-14x-5=0
The quadratic coefficient is 1
The coefficient of the first term is - 14
The constant term is - 5

The square of 3 (x + 1) is 48. How to solve and write the process in detail
solve

3(x+1)(x+1)=48
(x+1)^2=16
x+1=±4
X = 3 or - 5

52X minus the square of x plus 100 equals zero. Find out how much x equals

52x-x^2+100=0
x^2-52x-100=0
According to the root formula
52±√（52^2+400
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two

How to solve the equation x-52x-320 = 0

x²-52x=320
x²-52x+676=520+676=1196
(x-26)²=(±2√299)²
x-26=±2√299
x=26-2√299,x=26+2√299

How much is x equal to the square of X + 52X = 52?
It's been a long time since I graduated. I've forgotten all the formulas,
But after looking at the formula on the first floor, it suddenly occurred to me
x²+52=52²
x²+52x+26²=52²+26²
(x+26)²=3380
x+26=58.137767414995
x=52-26
x=26

x²+52x=52
x²+52x+26²=52+26²
（x+26)²=728
x+26=±2√182
x=-26±2√182

-The square of 52X minus 8448x minus the value of X in 278528 = 0

-52X^2-8448X-278528=052X^2+8448X+278528=013X^2+2112X+69632=0X1=(-2112+(2112^2-4*13*69632)^0.5)/(2*13)=(-2112+(839680)^0.5)/26=(-2112+64*(205)^0.5)/26=(-1056+32*(205)^0.5)/13X2=(-2112-(2112^2-4*13*6963...

University (solution) LIM (x-1) * 52X (2x-8) * 48 / (5x + 7) * 100, * is a square number, followed by its number, X tends to infinity

After expansion, the first formula of the molecule is divided by 52 times of X, the second term of the molecule is divided by 48 times of X, and the denominator is divided by 100 times of X. except for the highest term, all the other terms are n times of X, which is zero. So the answer is 48 times of 2 divided by 100 times of 5

x/1*3+x/3*5+… Process reconciliation of X / 2007 * 2009 = 2009

X / 1 * 3 = x / 2 * (1 / 1-1 / 3, other numbers are the same,
x/1*3+x/3*5+… X / 2007 * 2009 = x / 2 * (1-1 / 3 + 1 / 3-1 / 5... + 1 / 2007-1 / 2009) = x / 2 * (1-1 / 2009) = 2009, x = 2009 ^ 2 / 1004

When x takes what value, | X-1 | + | X-2 | + | x-3 | + +|X-2007 | get the minimum, what is the minimum?

On the number axis, to make the distance sum of point x to two fixed points minimum, then x is between two points, and the minimum value is the length of line segment with two fixed points as endpoints (otherwise, the distance sum is greater than the line segment); therefore, when 1 ≤ x ≤ 2007, | X-1 | + | x-2007 | has the minimum value of 2006; when 2 ≤ x ≤ 2006, | X-2 | + | x-2006 | has the minimum value of 2004 In conclusion, when x = 1004, | X-1 | + | X-2 | + | x-3 | + |X-2007 | can take the minimum value, the minimum value is: | 1004-1 | + | 1004-2 | + | 1004-3 | + |1004-2007|=1003+1002+1001+… +0+1+2+1003=1004×1003=1007012．

Find the minimum value of | X-1 | + | X-2 | + | x-3 | + | x-4 | + | X-5 | +... + | x-2007 |

When x = 1004, the value of the original formula is the smallest
The minimum value is 2 (1003 + 1002 +...) +1）
=2（1+1003）×1003÷2
=1004×1003
=1007012