Given the length of the three sides of a triangle, can we find the area? How? And we don't give the degree of the angle

Given the length of the three sides of a triangle, can we find the area? How? And we don't give the degree of the angle

According to the length of three sides, the cosine value cosa = (b ^ 2 + C ^ 2-A ^ 2) / 2BC of an angle can be obtained by cosine theorem, and then the sine value can be obtained by Sina ^ 2 + cos ^ 2 = 1, and the area is equal to s = bcsina
(small letters are the length of the side, and capital letters are the corners)

Given the length of the three sides of a triangle, find the area of the triangle
The base is 5cm, one side is 4cm and the other side is 3cm

The bottom edge is 5cm, one side is 4cm, the other side is 3cm,
Is a right triangle, 5 is a hypotenuse,
The area is 1 / 2 * 3 * 4 = 6 (bisects cm)

Given the length of one side of the triangle and its diagonal degree, the radius of the circumcircle of the triangle, find the maximum area of the triangle

Let the area of a B triangle on the other two sides of the known angle c be equal to 0.5 times absinc, and because sinc is divided by C = 2R (R is the radius of circumscribed circle), the area is equal to 0.5 * abc2r, and then we use the first cosine theorem that the second power of C = the second power of a + the second power of B - 2abcosc, because the known side length and angle can be transformed into a B relationship

The area of a triangle is 48 square centimeter, the area of B triangle is 9 / 50 of parallelogram, find the area of parallelogram
Two times a and B are parallelograms

Let the area of a parallelogram be X
The area of triangle B is (9 / 50) * X
That is 48 + (9 / 50) * x * 2 = x
The solution is x = 75

A parallelogram is 15 decimeters low and 8 decimeters high. It has the same area as another triangle, low, and this triangle is high

Quadrilateral area = 8 * 15 = 120 DM2
Let the height of triangle be X
The triangle area is 0.5 * x * 15 = 120
X=16
The height is 16 decimeters

How to calculate the area of a triangle whose three sides are 7; 4.5; 3.8
Triangles are irregular

Method 1: Helen qinjiu formula is known triangle three sides a, B, C, then s area = √ [P (P - a) (P - b) (P - C)] (Helen formula) (where p = (a, B, c) / 2) method 2: make height method: make height of one side, use Pythagorean to define understanding, method 3: cosine method, from cosa = B ^ 2 C ^ 2-A ^ 2 / 2BC

In triangle ABC, a = 7, B = 3, C = 8?
First use cosine function to find COSC, and then there is a formula for area. Forget it. Who can tell me

The area formula is
0.5*a*b*sinC
Find COSC first, then sinc

In the triangle ABC, if a = √ 7, B = 3, C = 2, then its area is equal to

cosC=

In △ ABC, if the lengths of the three sides are 9, 12 and 15 respectively, then the area of the rectangle formed by such triangle is 0______ ．

According to the inverse theorem of Pythagorean theorem, a triangle is a right triangle, and the lengths of its two short sides are 9 and 12 respectively. The area of a rectangle made of such a triangle is 9 × 12 = 108

In the triangle ABC, the angle c is a right angle, AC = 16 cm, BC = 12 cm. If the length EF of the rectangle cdef is twice the width De, the area of the rectangle can be calculated
Point E is on AB, point D is on AC, and point F is on BC

I understand. This topic is actually very simple. You see, the length EF of the rectangular cdef is twice the width De, and then pay attention to the triangle DEA. Have you noticed that the triangle DEA is similar to the triangle ABC, and the ratio of their three sides is 3:4:5