The side length of the square is 10 cm. The area of triangle a is 20 cm less than that of triangle B. find the length of line ab

The side length of the square is 10 cm. The area of triangle a is 20 cm less than that of triangle B. find the length of line ab

The area of triangle a is 20 square centimeter smaller than that of triangle B. according to the figure, the area of triangle DCB is 20 square centimeter larger than that of square CDEA, so the area of triangle DCB is: 10 × 10 + 20 = 100 + 20 = 120 (square centimeter), and because the side length of square CD = 10 cm, so CB's

The side length of the square is 10 cm. The area of triangle a is 20 cm less than that of triangle B. find the length of line ab

The area of triangle a is 20 square centimeter smaller than that of triangle B. according to the figure, the area of triangle DCB is 20 square centimeter larger than that of square CDEA, so the area of triangle DCB is: 10 × 10 + 20 = 100 + 20 = 120 (square centimeter), and because the side length of square CD = 10 cm, so CB's

The side length of the square is 10 cm. The area of triangle a is 20 cm less than that of triangle B. find the length of line ab

The area of triangle a is 20 square centimeter smaller than that of triangle B. according to the figure, the area of triangle DCB is 20 square centimeter larger than that of square CDEA, so the area of triangle DCB is: 10 × 10 + 20 = 100 + 20 = 120 (square centimeter), and because the side length of square CD = 10 cm, so CB's