The area of the overlapping part of the two figures is equivalent to 2 / 13 of the area of the large rectangle and 3 / 10 of the area of the small rectangle 1: The area ratio of large rectangle to small rectangle is (:) 2: If the area of the overlap is 18 square centimeters, the total area covered by the two rectangles is () square centimeters

The area of the overlapping part of the two figures is equivalent to 2 / 13 of the area of the large rectangle and 3 / 10 of the area of the small rectangle 1: The area ratio of large rectangle to small rectangle is (:) 2: If the area of the overlap is 18 square centimeters, the total area covered by the two rectangles is () square centimeters

1、39：20
2、159
1. Let the shadow area be x, so the area of large rectangle is 13 / 2x, and that of small rectangle is 10 / 3x
So the area ratio of large and small rectangles is 13 / 2x: 10 / 3x = 39:20
2. If x = 18, the large rectangle is 13 / 2 * 18 = 117, and the small rectangle is 10 / 3 * 18 = 60
So the coverage area is 117 + 60-18 = 159

The overlapping area of the two figures is equivalent to 2 / 13 of the area of the large rectangle and 3 / 10 of the area of the small rectangle
If the overlap area is 18 square centimeters, what is the total area covered by two rectangles?

Large rectangle area = 18 × 13 / 2 = 117
Small rectangle area = 18 × 10 / 3 = 60
Total coverage area = 117 + 60-18 = 159

As shown in the figure, the length of the rectangle is 16 cm, and the width is 10 cm?

Use 16 × 10 to calculate the holding area, and then calculate the non shadow area according to the conditions of the question. Subtract the non shadow area from the rectangular area, that is the shadow area. Welcome your questions and answers in the future. I'm in the third grade of junior high school. I wish you a good time