If the perimeter of a right triangle is 14cm and the length of its hypotenuse is 6cm, what is its area? Such as the title

If the perimeter of a right triangle is 14cm and the length of its hypotenuse is 6cm, what is its area? Such as the title

Let X be the length of one of the right angles
X & sup2; + (8-x) & sup2; = 6 & sup2; gives x = 4 ± root 2
That is, the lengths of the two right angles are (4 + radical 2) (4-radical 2)
Then the area is 1 / 2 * (4 + radical 2) (4-radical 2) = 7

If the perimeter of a rectangle of length 4 and width 2 is equal to that of a right triangle, and the area of the right triangle is 6, what is the length of the hypotenuse?

The perimeter of right triangle is: (4 + 2) * 2 = 12 (CM)
Only the sum of Pythagorean numbers of 3, 4 and 5 is 12, so the hypotenuse is 5
We can verify that 3 * 4 / 2 = 6
Prove that the hypotenuse is 5
I hope you can be satisfied with my answer!

The school plans to divide the task of planting trees to grade 6 and other grades according to 5:3. Results the number of trees planted in Grade 6 accounts for 75% of the whole school, 20 more than the plan. How many trees did the school plan to plant?

5 + 3 = 8.20 (75% - 58), = 20 (34 − 58), = 20 (18), = 160 (trees)