As shown in the figure, we know that the perimeter of an isosceles triangle is 16, and the height of its bottom edge is 4

As shown in the figure, we know that the perimeter of an isosceles triangle is 16, and the height of its bottom edge is 4


Let BD = x, then AB = 8-x. from Pythagorean theorem, we can get AB2 = BD2 + ad2, that is, (8-x) 2 = x2 + 42, ∧ x = 3, ∧ AB = AC = 5, BC = 6



As shown in the figure, we know that the perimeter of an isosceles triangle is 16, and the height of its bottom edge is 4


Let BD = x, then AB = 8-x. from Pythagorean theorem, we can get AB2 = BD2 + ad2, that is, (8-x) 2 = x2 + 42, ∧ x = 3, ∧ AB = AC = 5, BC = 6



As shown in the figure, we know that the perimeter of an isosceles triangle is 16, and the height of its bottom edge is 4


Let BD = x, then AB = 8-x. from Pythagorean theorem, we can get AB2 = BD2 + ad2, that is, (8-x) 2 = x2 + 42, ∧ x = 3, ∧ AB = AC = 5, BC = 6



An isosceles triangle with a circumference of 18. One side is 8 long. What are the lengths of the other two sides/


(1) The other two sides are: (18-8) / 2 = 5
Or (2) 18-8 * 2 = 2, the bottom is 2, and the other two are 8. Do you understand me