3m-2n=11,4m-n=-1 Five minutes!

3m-2n=11,4m-n=-1 Five minutes!


3m-2n=11,4m-n=-1
8m-2n=-2
Subtracting 5m = - 13 m = - 13 / 5
n=4m+1=4x(-13/5)+1=-47/5



Calculation: (x ^ m + n) ^ 2 · (- x ^ m-n) ^ 3 + x ^ 3m-n '(- x ^ 3) ^ m


M is an odd number
The original formula = x ^ (2m + 2n) * (- x ^ (3m-3n)) + x ^ (3m-n) * (- x ^ (3m)
=-x^(5m-n)-x^(6m-n)
M is even
The original formula = x ^ (2m + 2n) * (- x ^ (3m-3n)) + x ^ (3m-n) * x ^ (3m)
=-x^(5m-n)+x^(6m-n)



If x ^ m = 3, x ^ n = 6, then x ^ 3m-2n=__


x^3m-2n
=x^3m÷x^2n
=(x^m)³÷(x^n)²
=3³÷6²
=3/4



If x ^ m = 2, x ^ n = 3, find x ^ 3M + 2n


72



2m-n = 7, - M-N = 5, r = 3m-2n how to calculate R is equal to


N = 17 / 7, M = 33 / 7, r = 65 / 7, you can try to replace all the numbers



There is a snail in a dry well. The snail climbs up 3m in the daytime and slides down 2m at night. On the tenth day, the snail just reaches the wellhead to find out how deep the well is


The well is 12 meters deep
Climb 3-2 = 1 (m) per day for the first nine days
9 meters in total
On the tenth day, climb up in the daytime, no slide, climb 3 meters
Well depth 3 + 9 = 12m



The snail climbs up the shaft wall at the bottom of the well. It climbs 3 meters in the daytime and retreats 2 meters on the net. A well is 12 meters deep


Because the last time I climbed 3 meters, it was 9 meters before, 1 meter every day, 9 + 1 = 10 days



(1 / 3) in a well, the water surface is 3M lower than the wellhead. A snail climbs up along the well wall from the water surface. After climbing up 0.5m for the first time, it slides down 0.1M
(1 / 3) in a well, the water surface is 3M lower than the wellhead. A snail climbs up along the shaft wall from the water surface. After climbing up 0.5m for the first time, it slides down 0.1M. After climbing up 0.42m for the second time, it goes down again


3-0.5+0.1=2.6m
2.6-0.42+0.15=2.33m
2.33-0.7+0.15=1.78m
1.78-0.75+0.1=1.13m
1.13-0.55=0.58m
0.58-0.48=0.1m
It is 0.1M away from the wellhead and does not climb out of the wellhead



There is a 9-meter-deep well. The snail and the tortoise climb up from the bottom of the well at the same time. Because the wall of the well is slippery, the snail climbs up 2 meters during the day and down 1 meter at night. The tortoise climbs up 3 meters during the day and down 1 meter at night. When the tortoise climbs to the wellhead, the snail is () meters away from the wellhead
A. 4B. 4.5C. 5D. 5.5


Tortoise: 3-1 + 3-1 + 3-1 + 3 = 9 (m), snail: 2-1 + 2-1 + 2-1 + 2 = 5 (m), snail distance from wellhead: 9-5 = 4 (m); answer: when tortoise climbs to wellhead, snail distance from wellhead is 4 M



In a well, the water surface is 3M lower than the wellhead. A snail climbs along the wall of the well to the wellhead, climbing up 0.5m for the first time, and then sliding down 0.1M;


3-0.5+0.1=2.6m
2.6-0.42+0.15=2.33m
2.33-0.7+0.15=1.78m
1.78-0.75+0.1=1.13m
1.13-0.55=0.58m
0.58-0.48=0.1m
It is 0.1M away from the wellhead and does not climb out of the wellhead