If the height of the hypotenuse of a right triangle divides the hypotenuse into two parts with lengths of 4 and 9, what is the area of the right triangle? A.38B.39C.40D.41

If the height of the hypotenuse of a right triangle divides the hypotenuse into two parts with lengths of 4 and 9, what is the area of the right triangle? A.38B.39C.40D.41


B. 39 high * high = 4 * 9 high = 6
Area = (4 + 9) * 6 / 2 = 39