When m is the value, the values of the algebraic formula 5m + 14 and 5 (M-14) are opposite to each other?

When m is the value, the values of the algebraic formula 5m + 14 and 5 (M-14) are opposite to each other?

According to the meaning of the question: 5m + 14 + 5 (M-14) = 0, remove the brackets: 5m + 14 + 5m-54 = 0, transfer and merge: 10M = 1, the solution: M = 110

Simplification: M + | (1 + m ^ 2-2m) / (m-1)|

Because 1 + m ^ 2-2m = (m-1) ^ 2,
Therefore, the original formula = m + | (m-1) ^ 2 / (m-1) | = m + | (m-1) |,
Because m ≠ 1, when m > 1, the original formula = m + M-1 = 2m-1;
When m

How to simplify 2m ^ 2 + M-1

2m^2+m-1=(m+1)(2m-1)

(3 / 2) ^ 2 - (2m-8) * 3 / 2 + m ^ 2-16 reduction,
(3 / 2) ^ 2 - (2m-8) * 3 / 2 + m ^ 2-16 simplification, what I need most is process
4m^2-12m-7

(3/2)^2-(2m-8)*3/2+m^2-16
=9/4-3m+12+m^2-16
=m^2-3m-7/4

Given the circular equation x square + y square + 4x-6y = 0 and the straight line y = 3x + B, find the linear equation when the straight line y = 3x + B is tangent to the circle

The standard equation of circle is: (x + 2) ^ 2 + (Y-3) ^ 2 = 13
When tangent, the distance from the center of circle (- 2,3) to the straight line is equal to the radius, then
｜-6-3+b｜/√10＝√13
b＝9±√130
The linear equation is y = 3x + 9 ± √ 130

Please write a quadratic equation with one variable whose root is x = 1 and the other satisfies - 1 < x < 1______ ．

From the meaning of the question, when the other root is 0, it satisfies - 1 < x < 1. The equation can be: X (x-1) = 0, which is reduced to x2-x = 0. So the answer is x2-x = 0

Please write one root as x = - 1, and the other root satisfies - 1

It's very simple. According to Weida's theorem, if the two real roots of the equation AX ^ 2 BX C = 0 are x1, X2, then X1 x2 = - B / A, X1 * x2 = C / A. therefore, if the other root is - 0.5 and a = 1, then X1 x2 = 1.5, X1 * x2 = 0.5, that is, the equation is x ^ 2 1.5x 0.5 = 0
Similarly, many equations can be written with different values of the other root

Please write that one root is x = 1 and the other satisfies - 1

For example, if the other root is 0, then the sum is 1, the product is 0, and the equation is x ^ 2-x = 0

Write a quadratic equation of one variable about X with a root of - 1

x^2-1=0

Fill in the blanks:
Construct a quadratic equation with one variable so that one root is 1 and the other root satisfies - 1 is less than x is less than 1
Unfilled column:
Given that a is the root of the quadratic equation (x + 5) (2x-3) = - 15, and a ≥ 0, find the value of the algebraic formula A & sup2; - 4 / 4 + z-a 2 / 4

1. X ^ 2-x = 0 (one root is 1, one root is 0, in accordance with)
2、（x+5)(2x-3)=-15
2X^2-3X+10X-15=-15
2X^2+7X=0
X(2X+7)=0
X1=0 X2=-7/2
Because a ≥ 0, a = 0
After that, you can substitute a = 0