To solve the equations, x + y = 3x-2y = 10 + 6x + y

To solve the equations, x + y = 3x-2y = 10 + 6x + y

The system of equations composed of the first two equations can be solved to x = y, and then it can be substituted into the system of equations composed of one or three two equations to get x = y = - 10 / 3

Solving equations {3x + 2Y = 7 {6x-2y = - 1 solving equations {4 (X-Y) = 3 (1-y) + 2 {2 / x + 3 / y = 2
Solving the equations {4 (X-Y) = 3 (1-y) + 2
{2 / x + 3 / y = 2

Hello! First calculate the first group: 3x + 2Y = 76x-2y = - 1, add it to get 9x = 6, x = 2 / 3, bring it into the first equation, get 3 * 2 / 3 + 2Y = 72 + 2Y = 7, get y = 5 / 2, so x = 2 / 3, y = 5 / 2. The second group equation: 4x-4y = 3-3y + 2, that is 4x-y = 52 / x + 3 / y = 2, multiply both sides by XY, that is 2Y + 3x = 2XY, this is a binary quadratic

The following system of linear equations with two variables 1.3x = 2Y + 4,6x + 2Y = 5.2.2 of x-y-6 of X + y = 1,3 (x + y) = 2 (X-Y) + 10 are solved by proper methods

3x=2y+4
Available
3x-2y=4
Available
6x-4y=8
From 6x + 2Y = 5
Minus 6x-4y = 8
We can get y = - 1 / 2
We can get x = 1
From X / 2-y-x / 6 + y = 1
We can get x = 3
Substituting 3 (3 + y) = 2 (3-y) + 10
We can get 9 + 3Y = 6-2y + 10
We can get 5Y = 7
We can get y = 7 / 5 = 1.4