Let 1 be less than and equal to x, less than and equal to 2, 1 be less than or equal to y, and less than or equal to 2, then the value range of 3x-2y is?

Let 1 be less than and equal to x, less than and equal to 2, 1 be less than or equal to y, and less than or equal to 2, then the value range of 3x-2y is?

1≤Y≤2,
2≤2Y≤4
-4≤-2Y≤-2 ①
3≤3X≤6 ②
①+②,-1≤3X-2Y≤4

If the solution of the system of equations 3x-y = 2m + 1, x + 2Y = 8 satisfies that X-Y is greater than or equal to 6, the range of M can be obtained

Take M as the constant x + 2Y = 8, the equation × 3, and then subtract 3x-y = 2m + 1 to get 7Y = 23-2m-1, y to get 23-2m-7, then substitute the number of Y into x + 2Y = 8 to get x = 33 + 2m-7, and substitute them into X-Y ≥ 6 to get m ≥ 8

Given y = - 3x + 6, the value range of X can be obtained according to the following conditions: y is greater than or equal to 2
I don't care whose answer it is, as long as you are right,

y=-3X+6≥2
-3x≥-4
x≤4/3