The square of the difference between 2x and 1 is 16. Find X

The square of the difference between 2x and 1 is 16. Find X

(2x-1)²=16
2x-1=-4,2x-1=4
x=-3/2,x=5/2

(a square + b square) (a square + b square - 8) - 16 = 0, then a square + b square=

(a^2+b^2)(a^2+b^2-8)-16=0
Let a ^ 2 + B ^ 2 = t > 0
t(t-8)-16=0
t^2-8t-16=0
T = 4 + 4 radical 2
So a ^ 2 + B ^ 2 = 4 + 4 radical 2

Given the function y = (a ^ 2-3a) x ^ (a ^ 2-a-1), (1) when finding the value of a, y is a positive proportion function of X, (2) when finding the value of a, y and X are inverse proportion functions

1. A ^ 2-3a ≠ 0 a ^ 2-a-1 = 1 a = 2 or - 1
2.a^2-3a≠0 a^2-a-1=-1 a=1

First simplify and then evaluate: x plus the square of 2 / 2 x minus 1 divided by (x plus 1 / 2 minus 1), where x is equal to 1 / 3, how to calculate?
As the title!

It is reduced to - x + 1
Substituting for value 2 / 3

X squared - 7x + 12 divided by (- x squared plus 9x-20)

X squared - 7x + 12 divided by (- x squared plus 9x-20)
=（x-3)(x-4)/[-(x-4)(x-5)]
=(x-3)/(5-x)

The minimum value of function y = x ^ 2 + 7x + 10 / (x + 1) (x > - 1)?
Can we use the mean inequality? I know how to use it. It's 9. But there's no 9 in the options!
A. 6 B.2 radical 5 + 5 C. radical 5 + 10 D.2 radical 6 + 5
I'm so stupid!

The answer is 9, molecular expansion: x2 + 7x + 10 = (x + 1) 2 + 5 (x + 1) + 4, divided by denominator, Ymin = x + 1 + (4 / x + 1) + 5 > = 2 open root (x + 1) * (4 / X + 1) + 5 = 9

The minimum value of y = x2 + 7x + 10x + 1 (x ＞ - 1) is______ ．

∵ x ＞ - 1, ∵ x + 1 ＞ 0. Y = x2 + 7x + 10x + 1 = (x + 1) 2 + 5 (x + 1) + 4x + 1 = (x + 1) + 4x + 1 + 5 ≥ 2 (x + 1) · 4x + 1 + 5 = 9 if and only if x = 1. The minimum value of