If the average of data x1, X2, X3... Xn is 8, then the average of data 4 (x1-3), 4 (x2-3), 4 (x3-3), 4 (xn-3) is?

If the average of data x1, X2, X3... Xn is 8, then the average of data 4 (x1-3), 4 (x2-3), 4 (x3-3), 4 (xn-3) is?

If the average of data x1, X2, X3... Xn is 8, then the average of data 4 (x1-3), 4 (x2-3), 4 (x3-3), 4 (xn-3) is? From the average of data x1, X2, X3... Xn is 8, we know: X1 + x2 + x3 +... + xn = 8 * n, and 4 (x1-3) + 4 (x2-3) + 4 (x3-3) +. + 4 (xn-3) = 4 (x1 + x2 + X3 +... + xn) + 4 * (- 3)

Given that the average of a group of numbers x1, X2, x3 ·· xn is 4 and the variance is 2, then the average of 5x1, 5x2, 5x3 is 4_____ The variance is_____

The average is 20, and the variance is 20, and the average is 20, and the variance is 50x1 + x2 + X3 +. + xn = 45x1 + 5xx2 + 5xx + 5xx + 5xn = 5 * (x1 + x2 + X + X + x n = 5 (x1 + x2 + X + X + X + x n = 5 + X + X + X + x = 45x1 + 5xx1 + 2x2 + X + 2xn = 45x1 + 5xx1 + 5xx + 5xx + 5xx + 5xx + 5xx + 5xx + 5xx + X + X + X + x x + X + X + X + X + X + 2XX + X + 2XX + X + X + 2XX + X + X-2 + X-2 + X + X + X + 2XX + X + X + X + X + X + X + x-2x2xx + X + X + X + 2x2x2x2xx + X + 2XX + 2x2xx + X + X + 2x2x2x2x2xx + X + 2XX + 2XX + 2x5xn-20) &

Solve the following linear equations X1 + 2x2 + 3x3 = 1 2x1 + 2x2 + 5x3 = 2 3x1 + 5x2 + X3 = 3

The way to do this problem is: first select two equations, eliminate an unknown number can get a new equation, and then select two equations (the two equations are completely repeated with the previous two), eliminate the same unknown number and get a new equation, the two new equations can solve two unknowns, the solution of the two