f(x)=5（x≤1） f(x)=1／x-1(x﹥1) f(5)= f(1／2)= f(x)=5（x≤1）f(x)=1／x-1(x﹥1)f(5)=f(1／2)=

f(x)=5（x≤1） f(x)=1／x-1(x﹥1) f(5)= f(1／2)= f(x)=5（x≤1）f(x)=1／x-1(x﹥1)f(5)=f(1／2)=

∵5>1
Use the second expression
∴f(5)=1/（5-1）=1/4
∵1/2

If f (x) = x + 1 / x + 5, then f '(1)=
The inner one is 1 / x, not 1 / x + 5

First, the function is derived, and then 1 is substituted, f '(x) = 1-1 / x ^ 2, f' (1) = 0;

How does f (x) - f (1 / X-5) = f (x (X-5)) come from?

By using f (x) = f (x / y) + F (y), f (x) - f (y) = f (x / y), and substituting x = x, y = 1 / (X-5), we can get f (x) - f (1 / (X-5)) = f (x / 1 / (X-5)), = f (x (x (X-5))

75 divided by (0. 24 divided by 0. 3), recursive equation

0.75 divided by (0.24 divided by 0.3)
=0.75÷0.8
=75÷80
=0.9375

If two numbers are divided, the quotient is 102. If the divisor and divisor are reduced by 6 times at the same time, the quotient is 102______ ．

If two numbers are divided, the quotient is 102. If the divisor and divisor are reduced by 6 times at the same time, the quotient is 102

Divide two numbers, the quotient is 30, the divisor divided by 2, the divisor also divided by 2, what is the quotient at this time?

15

What is 7x = 6 / 14
6 / 14 is six fourths

x=6/98

X + 3 × (x + 1) equals 277x-2 (X-5) = 406x + 4 (10-x) = 46

x＋3×（x＋1）=27
x+3x+3=27
4x=24
x=6
7x-2（x-5）＝40
7x-2x+10=40
5x=30
x=6
6x＋4（10-x）＝46
6x+40-4x=46
2x=6
x=3

Find the positive integer solution of 2 (x + 1) greater than or equal to 7x-10

2(X+1)≧7X-10
2x＋2≧7X-10
5x≦12
x≦2·4
So the positive integer solution is 1,2

7x ^ 2-7x + 1 = 0 find out how much x is equal to,

7X^2-7X+1=0
x²-x-1/7=0
x²-x=1/7
x²-x+1/4=1/7+1/4=11/28
(x+1/2)²=11/28
x+1/2=±√（11/28）
x=-1/2±√（11*7/28*7）
=-1/2±√77 /14
Hope to help you_ ∩)O~