If a = 1 - √ 2, first simplify and then find the value of (A & # 178; - 1 / A & # 178; + a) + A & # 178; - 2A + 1 / A & # 178; - A

If a = 1 - √ 2, first simplify and then find the value of (A & # 178; - 1 / A & # 178; + a) + A & # 178; - 2A + 1 / A & # 178; - A

(a²-1)/(a²+a)+√（ a²-2a+1)/(a²-a)
=（a+1）（a-1）/【a（a+1）】-（a-1）/【a（a-1）】
=（a-1）/a-1/a
=1-2/a
=1-2/（1-√2）
=1+2（1+√2）………… Multiply the fraction by 1 + √ 2 at the same time
=3+2√2

|A + 2 | (B-1) & # 178; = 0, then the value of 2A AB is?
The result is not equal to - 2

|a＋2| +(b-1)²=0
be
a+2=0
b-1=0
be
a=-2
b=1
be
2a-ab=-4+2=-2
It's equal to - 2

6²π×10×x=25²π×35

6²π×10×x=25²π×35
x=25²π×35÷（6²π×10）
x=4375/72

Let I = R, a = {x | X & # 178; - X-6 ＜ 0}, B = {x | x-a ＞ 0} when a is what value, a ∪ B = {x | x ＞ - 2}
The answer is that a can be equal to 2, but when a = 2, it is a ∪ B = {x | x ≥ - 2}

It can be solved that a = - 2 - 2
There is no equal sign

If we know that one part of a + a = 3, then the value of one part of a &# 178; + a &# 178; is to find the diagram

a+1/a=3
(a+1/a)^2=9
a^2+1/a^2+2=9
a^2+1/a^2=7

It is known that if A-A 1 / 3 = 3, then a & # 178; + A & # 178; 1 / 3=

A ^ & # 178; + A ^ & # 178; 1 / 2 = (A-A 1 / 2) ^ 2 + 2 = 3 × 3 + 2 = 11 & nbsp; ~ 523 will always answer for you, I wish you progress in your study ~ ~ ~ if you agree with my answer, please click the [adopt as satisfactory answer] button in time ~ ~ the mobile phone questioner can comment "satisfied" in the upper right corner of the client. ~ your adoption is my driving force ~ ~ ~ if you have any new questions, please ask me for help, Please understand that the answer is not easy~~

A + 1 / a = 3, then a & # 178; + A & # 178; 1 / a =?

7

If 1 / 2 of A-A is known, what is the value of 1 / 178 of A-A

1 of A-A = 2,
A & # 178; + A & # 178; 1 / 2
=(a-1/a)²+2
=2²+2
=6

Given (A-2) &# 178; + | B + 2 | = 0, find the value of 1 / 2 of - A + B
.

∵(a-2)²+|b+2|=0
∴a-2=0,b+2=0
∴a=2 ,b=-2
∴1/(-a+b)
=1/(-2-2)
= -1/4

Given (a 2 + B 2) 2 - (a 2 + B 2) - 6 = 0, find the value of a 2 + B 2

Let A2 + B2 = y, y2-y-6 = 0, Y1 = 3, y2 = - 2 ∵ A2 + B2 ≥ 0 ∵ A2 + B2 = 3