Find the tangent slope of the curve y = 3x ^ 2-1 at x = 1?

Find the tangent slope of the curve y = 3x ^ 2-1 at x = 1?


y′=6x;
X = 1; y ′ = 6; that is, x = 1, tangent slope is 6;
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The slope of the tangent passing through a point a (1,2) on the curve y = 3x ^ 3


Because point a is not on the curve, and the tangent point is Q (a, 3A & \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\this



What is the slope of the tangent of the curve y = 2x square + 3 at point (- 1,5)
What do you do with derivatives


Y = 2x ^ 2 + 3, the derivation can be: y '= 4x, so x = - 1 generation
The solution is: y '= - 4, which is the slope of the tangent at the point (- 1,5)



5760 times 315 plus 521 / 206 plus 315 times 5770


3631950 and 206 / 521



Fill in the appropriate number in () as required, which is the multiple of 2 and 3: 206 (), 315 (), 98 (), 8 (), 2 (), 2
Fill in the appropriate number in () as required
Is a multiple of 2 and 3: 206 (), 315 (), 98 (), 8 (), 2 (), 2
Is a multiple of 2, 3, 5, 1 () 3 (), () 5 () 0, 1 () 6 (), 2 () 8 ()


Fill in the appropriate number in () as required
Are multiples of 2 and 3: 206 (4), 315 (0), 98 (2) 8, (1) 2 (1) 2
The mantissa is even, and the sum of the numbers is a multiple of 3
Is a multiple of 2,3,5, 1 (2) 3 (0), (1) 5 (0) 0,1 (2) 6 (0), 2 (2) 8 (0)
Note: the mantissa should be 0 and the sum of the numbers should be a multiple of 3
The answer is not unique
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Can 315 / 896 be simplified?





Fill in the appropriate number in () as required, which is the multiple of 2 and 3: 206 (), 315 (), 98 () 8, () 2 () 2 is the multiple of 2, 3 and 5,
Fill in the appropriate number in () as required
Is a multiple of 2 and 3: 206 (), 315 (), 98 (), 8 (), 2 (), 2
Is a multiple of 2, 3, 5, 1 () 3 (), () 5 () 0, 1 () 6 (), 2 () 8 ()


The mantissa of multiples of 2 should be: 0, 2, 4, 6, 8. The multiples of 3 should be such that the sum of the numbers in each digit is 3, 6, 9. For example, 111321 is a multiple of 3



Simplify the first two courses and fill in the blanks
[(1 / 6) x ^ 2 - (2 / 3) y ^ 2] / [(1 / 3) y - (1 / 6) x} (/ = fractional line)
0.5x ^ 2 + xy-1.5y ^ 2 / x ^ 2-y ^ 2 (/ = fractional line)
a^4-a^2 b^2/(a-b)^2 * b^2/a(a+b) * b^2/a
OK, here's 100


Mathematical answer group for you to answer, I hope to help you
[(1/6)x^2-(2/3)y^2] / [(1/3)y-(1/6)x}
=(1/6)[x^2-4y^2] / [(1/6)(2y-x)}
=(x+2y)(x-2y)/(2y-x)
=-x-2y
Please write down the last two questions clearly



To simplify the problem of 0.125:3 / 4,


0.125:3/4=(1/8):(3/4)=1:6



-3|c|+2|b|+4|b-a|


1, when a, B, C > 0, a > b, then
The original formula = - 3C + 2B + 4a-4b = 4a-2b-3c
2, when a, B, C > 0, a