How to calculate tangent slope of curve at a certain point in Excel

How to calculate tangent slope of curve at a certain point in Excel

Using MATLAB software

How to draw four irregular curves in excel?
I have four sets of data, each with 10000 numbers, which are irregular data. I need to convert the four sets of data into four curves and compare them in one graph. How can I do that? The key is how to draw four different curves in a coordinate graph. I can give you a clear answer. Specifically, I will give you 50 points

1. [insert] / [chart], select "line chart", there are continuous, point line, three-dimensional, any one, according to your situation, it is recommended to use the first line chart. 2, "next", select "data area", select all the data you need to underline

Given that the slope of the tangent line of a point B (1, b) on the image with the function f (x) = x ^ 3 + ax ^ 2 + 1 is - 3, find the value range of A,
Let the inequality f (x) be less than or equal to a-1993 for X to be greater than or equal to - 1 and less than or equal to 4

F (x) ≤ a-1993x & # 179; - 3x & # 178; + 1 ≤ a-1993x & # 179; - 3x & # 178; + 1994-a ≤ 0x & # 178; (x-3) ≤ a-1994f '(x) = 3x & # 178; - 6x ≤ 00 ≤ x ≤ 2 functions monotonically decrease on [0,2], monotonically increase on [- 1,0], monotonically increase on [2,4]. If the inequality holds for X ∈ [- 1,4]

The solution of equation 16x ^ 2 + 8x + 3 = 0?

16x^2+8x+3=0
(4x+1)^2=-2
4X + 1 = 2 under positive and negative I * radical
X = (2 - 1 under positive and negative I * radical) / 4
The root sign can't be typed, nor can it be positive or negative,

X ^ 2 + 17 = 8x use formula method to solve one variable linear equation

x^2+17=8x
x^2-8x+17=0
x^2-8x+16-16+17=0
(x-4)^2=-1
Because the square of the equation cannot be negative, there is no solution to the equation