What's the simplest fraction of 34 out of 51

What's the simplest fraction of 34 out of 51


thirty-four-fifty-firsts
=(34 / 17)
=2 / 3



51 out of 68 is the simplest fraction


3/4



Turn the following ratios into the simplest fraction ratio 51:17 = 1 / 5:1 / 6 = 0.125:2=


51:17=3:1
1/5:1/6=6:5
0.125:2=1:16



How to solve the equations 2 (X-Y) / 3 - (x + y) / 4 = - 1, 6 (x + y) - 4 (2x-y) = 16,


From (1)
8(x-y)-3(x+y)=-12
5x-11y=-12 (3)
From (2)
-2x+10y=16
-x+5y=8 (4)
(3)+(4)×5
14y=28
∴y=2
Substituting y = 2 into (4) yields
-x+10=8
∴x=2
∴x=2
y=2



Solve the equations, X / 3 + Y / 4 = 2, 2x-y = 6 process
Given that the images of the linear function y = ax + 6 and y = bx-2 intersect at the same point on the x-axis, then the value of B / A is?


In y = ax + 6, when y = 0, x = - 6 / A
In y = bx-2, when y = 0, x = 2 / b
Because they intersect at the same point on the x-axis, - 6 / a = 2 / b
So B / a = - 6 / 2 = - 3



Solve the equations (x + y) / 4 - (2x-y) / 3 = - 1 ① 6 (x + y) - 4 (2x-y) = 16 ②


(x+y)/4-(2x-y)/3=-1 ------------------------(1)
6(x+y)-4(2x-y)=16 ------------------------(2)
Let x + y = a, 2x-y = B, then the result is:
A/4-B/3=-1 ----------------------------(3)
6A-4B=16 ----------------------------(4)
(3) * 12: 3a-4b = - 12 ------ (5)
(4) (5) 3A = 28; a = 28 / 3
(4) - 2 * (5): 4B = 40, B = 10
Then: x + y = 28 / 3 -------- (6)
2x-y=10 ------------------------------(7)
(6) + (7): 3x = 58 / 3, x = 58 / 9
y=2x-10=26/9
x=58/9, y= 26/9



To solve the equations y △ 3 - < x + 1 > 6 = 32 < X-Y △ 2 > = 3 < x
To solve the equations y △ 3 - < x + 1 > 6 = 32 < X-Y △ 2 > = 3 < x + y △ 18 >


One third of Y minus one sixth of x = 19 times 6 at the same time, 2y-x = 19, then x = 2y-19, substituting x = 2y-19 into the second formula can remove the value of Y, and then substituting the value of Y into x = 2y-19 can get the value of X



Solving the equations (√ 3) x + (√ 2) y = 5 (√ 2) x + (√ 3) y = 2 √ 6


(√3)x+(√2)y=5··········① (√2)x+ (√3)y=2 √6·········②
① If ×√ 3-2 ×√ 2, x = 5 √ 3-4 √ 3  x = √ 3
Substituting x = √ 3 into (1) yields y = √ 2
The solution of the original equations is: x = √ 3, y = √ 2



Solve the equations {(x + y) / 2 + (X-Y) / 3 = 6 5 (x + y) - 2 (X-Y) = 4


(x+y)/2+(x-y)/3=6 ①
5(x+y)-2(x-y)=4 ②
From (1) we get 3x + 3Y + 2x-2y = 36 5x + y = 36 y = 36-5x (3)
From ②, we get that 5x + 5y-2x + 2Y = 4 3x + 7Y = 4 ④
③ Substituting 4, we get 3x + 252-35x = 4
32x=248
x=7.75
Substituting ③, y = 36-5 × 7.75 = - 2.75



How to solve the equations: 1,6 (X-Y) - 2 (X-Y) = 14,2,3 (X-Y) + (x + y) + 5
=5


6(x-y)-2(x-y)=14
3(x-y)+(x+y)=5
6x-6y-2x+2y=14
3x-3y+x+y=5
2x-2y=7 (1)
4x-2y=5 (2)
(1) - (2) get
-2x=2
x=-1
y=-9/2