If a = - (2009 × 2009-2009 / 2008 × 2008 + 2008), B =., C =., find ABC =? If a = - (2009 × 2009-2009 / 2008 × 2008 + 2008), B = - (2008 × 2008-2008 / 2007 × 2007 + 2007), C = - (2007 × 2007-2007 / 2006 × 2006 + 2006) Then ABC =?

If a = - (2009 × 2009-2009 / 2008 × 2008 + 2008), B =., C =., find ABC =? If a = - (2009 × 2009-2009 / 2008 × 2008 + 2008), B = - (2008 × 2008-2008 / 2007 × 2007 + 2007), C = - (2007 × 2007-2007 / 2006 × 2006 + 2006) Then ABC =?

-A = [2009 (2009-1)] / [2008 (2008 + 1)] = (2009 * 2008) / (2008 * 2009) = 1. = = = > A = - 1. Similarly, B = C = - 1. = = = > ABC = - 1

AB 1 + (a + 1) (B + 1) 1 + (a + 2) (B + 2) 1 +. + (a + 2008) (B + 2008) 1=
|Ab-2 | and | B-1 | are opposite numbers
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Let me give you an example
1/(1*2） +1/（2*3）+1/(3*4）+ 1/(4*5)
=(1-1 / 2) + (1 / 2-1 / 3) + (1 / 3-1 / 4) + (1 / 4-1 / 5) the key is to remove the brackets in this step, and the adjacent items will be eliminated
=1- 1/5
=4/5
I've seen your original question, and it turns out that if ab-2 + (B-1) ^ 2 = 0
The final answer is 2011 / 2012

Given a = 1, B = 2, try to find the value of: 1 / AB + 1 / (a + 1) (B + 1) + 1 / (a + 2) (B + 2) +. 1 / (a + 2008) (B + 2008)

The answer is 2009 / 2010
The original formula = 1 / 2 + (1 / 2-1 / 3) + (1 / 3-1 / 4) +... + (1 / 2009-1 / 2010). Then open the brackets

Ia-1i + ib-2i = 0, find the value of a + B (I is the sign of absolute value)

∵│a-1│≥0,│b-2│≥0
Also, A-1 + B-2 = 0
∴a=1,b=2
∴a+b=3
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