If the line L and the line x + Y-1 = 0 are symmetric about the Y axis, then the equation of the line L is______ ．

If the line L and the line x + Y-1 = 0 are symmetric about the Y axis, then the equation of the line L is______ ．

∵ the slope of the line x + Y-1 = 0 is - 1, and it intersects at (0,1) point on the Y axis, and ∵ the line L and the line x + Y-1 = 0 are symmetrical about the Y axis ∵ the slope of the line L is 1, and it passes through (0,1), then the equation of the line L is y = x + 1, that is, X-Y + 1 = 0, so the answer is: X-Y + 1 = 0

The method of solving the linear equation of known line about Y-axis symmetry in mathematics of senior two
The linear equation of 2x + 3y-6 = 0 with respect to Y-axis symmetry is______
What's the solution process like?
Later, if the line is symmetrical about the axis of symmetry (either X axis or Y axis)
Is it possible to solve the problem in this way!?

On Y-axis symmetry, X can be - 2x + 3y-6 = 0 by substituting - X
On X-axis symmetry, y can be substituted by - Y

Mathematics problem of grade two in Senior High School: with the linear equation of 3x-4y + 5 > 0 about X-axis symmetry
Not = 0. Yes > 0

Is it 3x-4y + 5 = 0? Its linear equation about X-axis symmetry is 3x + 4Y + 5 = 0