The function y is equal to x squared plus four x minus one, and the axis of symmetry of the image is

The function y is equal to x squared plus four x minus one, and the axis of symmetry of the image is

y=x²+4x-1
=(x+2)²-5
Axis of symmetry x = - 2

What is the symmetric equation of the function y equal to x squared minus 2x plus 3?
Just change to mathematical language

y=x^2-2x+3
=x^2-2x+1+2
=(x-1)^2+2
Axis of symmetry equation: x = 1

If the image of function y = f (x) is symmetric to the image of function y = 2x + 1 with respect to y = x + 1, then f (x) = ()
A. log2xB. log2（x-1）C. log2（x+1）D. log2x-1

F (x-1) and y = 2x are symmetric with respect to y = x, so f (x-1) = log2x, {f (x) = log2 (x + 1), so C

If △ ABC is an isosceles triangle, the image of a function y = X-1 intersects the coordinate axis at two points a and B, and point C is on the coordinate axis,
Please write at least 4 coordinates of point C that meet the condition

(0,0), (-1,0), （0,1）, (1+√2,0), (0,-1-√2)