x>_ Or X

x>_ Or X

That is X-1 > 0, x + 3

The solution equation: (1) 4x2-4x + 1 = x2 + 6x + 9 (2) (x + 4) 2 = 5 (x + 4)

(1) The transformation of the equation is (2x-1) 2 = (x + 3) 2, the root of the equation is: 2x-1 = x + 3 or 2x-1 = - x-3, the solution is: X1 = 4, X2 = - 23; (2) the transformation of the equation is: (x + 4) 2-5 (x + 4) = 0, the decomposition factor is: (x + 4) (x + 4-5) = 0, the solution is: X1 = - 4, X1 = 1

X2-6x + 9 / x2-4 x2-4x / x2-8x + 16 2 is the square / the fractional line

x2-6x+9/x2-4
=(x-3)²/（x+2）（x-2）
x2-4x/x2-8x+16
=x（x-4）/(x-4)²
=x/(x-4)