When x = 2, the value of the algebraic expression ax & # 179; + BX + 1 is 6, then when x = - 2, ax & # 179; + BX + 1 =?

When x = 2, the value of the algebraic expression ax & # 179; + BX + 1 is 6, then when x = - 2, ax & # 179; + BX + 1 =?

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It is known that when x = 2, the value of the algebraic expression ax & # 179; + BX + 6 is -- 7, then when x = - 2, the value of ax & # 179; + BX + 6 is -- 7

Solution
When x = 2
a*2³+2b+6=-7
When x = - 2
Primitive algebra = a (- 2) ³ + B (- 2) + 6
=-a*2³-2b+6
=-（a*2³+2b+6）+12
=-（-7）+12
=19

(1) It is known that when x = - 1, the value of the algebraic formula ax & # 179; + BX + 6 is - 10. When x = 1, the value of the algebraic formula ax & # 179; + BX + 6 is - 10. When x = 1, the value of the algebraic formula ax & # 179; + BX + 6 is - 10
(2) Given that x = 2, the value of the algebraic formula ax & # 178; + BX is 3. Find the value of (8a + 4b) &# 178; - 12a-6b-1

(1) When x = - 1, the value of the algebraic formula ax & # 179; + BX + 6 is - 10, that is: - A-B + 6 = - 10A + B = 16, when x = 1, the algebraic formula ax & # 179; + BX + 6 = a + B + 6 = 16 + 6 = 22 (2) x = 2, the value of the algebraic formula ax & # 178; + BX is 3, that is: 4A + 2B = 32A + B = 1.5 (8a + 4b) &# 178; - 12a-6b-1 = (4 (2a + b)) ^ 2-6 (2a + B