It is known that when x = - 1, the value of the algebraic formula ax & # 179; + BX + 6 is - 10. When x = 1, find the value of the algebraic formula ax & # 179; + BX + 6

It is known that when x = - 1, the value of the algebraic formula ax & # 179; + BX + 6 is - 10. When x = 1, find the value of the algebraic formula ax & # 179; + BX + 6

When x = - 1,
ax³+bx+6=-a-b+6=-10
So:
-a-b=-16
a+b=16
So when x = 1,
ax³+bx+6=a+b+6=16+6=22

It is known that when x = - 2, the value of the algebraic formula AX3 + BX + 1 is 6, then when x = 2, the value of the algebraic formula AX3 + BX + 1 is ()
A. 6B. -6C. 4D. -4

When x = - 2, the algebraic formula is - 8a-2b + 1 = 6, that is, 8A + 2B = - 5, then when x = 2, the algebraic formula is 8A + 2B + 1 = - 5 + 1 = - 4

The process of solving this equation is 0.25 (36 + x) = 0.36 (X-30)

0.25（36+x）=0.36（x-30）
25（36+x）=36（x-30）
900+25x=36x-1080
900+1080=36x-25x
1980=11x
x=1980/11
x=180