Factorization (x + y) ^ 3 + 2XY (1-xx-y) - 1 We must do it in a rotational way,

Factorization (x + y) ^ 3 + 2XY (1-xx-y) - 1 We must do it in a rotational way,




Help me: Factorization factor: x-y-xx + 2XY YY + 2 = 0


x-y-x^2+2*x*y-y^2+2
=-(x+1-y)*(x-2-y)
=0
x-y+1=0
x-y-2=0



Factorization of (XX BB + YY AA) - 4 (AB XY)


(x^2+4*x*y+y^2)-(b^2+4*a*b+a^2)=(x+y)^2-(a+b)^2
=(x+y+a+b)(x+y-a-b)