If the square of 5|2a + 1| + 4 (B-3) is known to be 0, then the B power of a + the B power of (2a) =?

If the square of 5|2a + 1| + 4 (B-3) is known to be 0, then the B power of a + the B power of (2a) =?

Because 5|2a + 1| + 4 (B-3) & sup2; = 0
So 2A + 1 = 0, B-3 = 0
a=-1/2,b=3
The power B of a + the power B of (2a) = (- 1 / 2) & sup3; + (- 1) & sup3; = - 1 / 8-1 = - 9 / 8

2A / 2 of 3b to the third power of (- A / b)

Solution
2a/3b÷(-a/b)³
=-(2a/3b)×(b³/a³)
=-2b²/3a²

If - ax ^ 6 is a quartic monomial about X, y and the coefficient is 8, find the value of a and B

Is it y ^ B?
For the quartic monomial, then 1 + B = 4
Coefficient - a = 8
So a = - 8, B = 3