How to calculate the square root of addition For example: √ 32-3 √ 1 / 2 + √ 1 / 8

How to calculate the square root of addition For example: √ 32-3 √ 1 / 2 + √ 1 / 8

Original formula = √ (16 * 2) - (√ 1) / (√ 2) + (√ 1) / (√ 8)
=4*√2-(1/2)*√2+(1/4)√2
=(4-1/2+1/4)*√2
=(14/5)*√2

What is the square root of 0.314, 0.314, 3.14, 31.4, 314, 3140? Please give me 3Q

The square roots of 0.0314, 0.314, 3.14, 31.4, 314, 3140 are ± 0.177, ± 0.56, ± 1.772, ± 5.604, ± 17.72, ± 56.035

314 square root

17 square = 289 18 square = 324 17

What is the number whose square root equals 0.0001 itself?

0.01

Is the root two of two (the square root of two) a rational number?

It's not rational. It should be irrational
Irrational numbers refer to some infinitely acyclic decimals,
Rational numbers, on the contrary, are circulable and regular numbers. All the numbers we are studying are rational numbers. On the contrary, integers and fractions are called rational numbers

If y = (root 2x-1) + (root 1-2x) + 1 / 3, then x = (), y = () if (root x-1) + (root 1-x) is meaningful, then the square root of X is ()
Find the value of X: 4 (x-1) ^ 2 = 25
It is known that X and y are real numbers, and y = (radical X-9) - (radical 9-x) + 4
Write down the specific process in question 3 and 4

1、x=1/2 y=1/3
2. Plus or minus 1
3、x1=3.5 x2=-1.5
4. 3 and 2
Believe me, that's right!
3、4(x-1)^2=25
(x-1)^2=25/4
x-1=±√25/4
x-1=±5/2
∴x=3.5
x=-1.5
4. Y = radical x-9-radical 9-x + 4
Because the value inside the root sign must be greater than or equal to 0
therefore
x-9≥0
9-x≥0
So X-9 = 9-x = 0
x=9
y=4
Root x = 3, root y = 2

Given root 3x-1 = root 10, the cube root of Y + 1 = 3, find the square root of 3x + y

x=11/3,y=26
3x+y=(3*3/11+26)^1/2=37^1/2

The square roots of 2x-1 are A-7 and 3a-1. Find the value of X

a-7+3a-1=0
4a=8
a=2
a-7=2-7=-5
2x-1=(-5)²=25
2x=26
x=13

Find X in the following questions: (1) the square roots of X are positive and negative; (2) the square roots of X + a are positive and negative; (3) the square roots of 2x-1 are A-3 and 3a-1

Because the square root of X is ± 2, x = 4
2, because the square root of X + A is ± a, then a & # 178; = x + A, so x = A & # 178; - A
3, because A-3 and 3a-1 are the square roots of 2x-1, so A-3 + 3a-1 = 0, so a = 1, so 2x-1 = 4. X = 5 / 2

Xiao Mahu solves the equation 2x-1 / 3 = x + A / 2 - 1, the denominator is removed, the - 1 on the right side of the equation forgets to multiply by 6, so the solution obtained is x = 16, try to find the value of a, and correctly solve the equation

2x-1/3=x+a/2 -1
Six on both sides, not one
12x-2=6x+3a-1
6x-1=3a
a=2x-1/3
The solution is x = 16, so a = 16 * 2-1 / 3 = 95 / 3
Correct solution
2x-1/3=x+a/2 -1
12x-2=6x+3a-6
6x=3a-4
Because a = 95 / 3
So 6x = 91
x=91/6