The least common multiple of 32 and 8

The least common multiple of 32 and 8

Because 32 is a multiple of 8, the least common multiple of 32 and 8 is 32

The least common multiple of 32 and 30

480

The least common multiple of 32 and 25

32×25＝800

From the six numbers 0.1.2.3.4.5, take four at a time to form several even numbers without repetition?

1、 There are three possibilities in one digit. 2. Suppose that zero is not used in one digit, there are two possibilities in two and four. 1. Thousand digit has four possibilities except zero and one digit. 2. After determining one digit and one thousand digit, there are four possibilities in one hundred. 3. After determining one digit and one thousand digit and one hundred digit, there are three possibilities in ten digit, so the number is 2 × 4 × 4 × 3

The even number of 3 digits without repetition can be made up of the four digits of 0, 2, 3 and 4

The total is 4 × 3 × 2 = 24 species
3 × 2 = 6
Subtracting the last not 3 but the first 0: 4
The results are as follows
24-6-4 = 14 species
They are listed as follows:
204、230、234、240、302、304、320、324、340、342、402、420、430、432

Mathematics problems in the first half of the second semester of junior high school (square root)
(1 / 3A + √ 3 / 2a) + (1 / 4 - √ 3 / 12) B-2 and 1 / 4-20 / 29 ×√ 3 = 0
(1 / 3 a plus 2 / 2 root sign 3 A) plus (1 / 4 minus 12 / 3 root sign 3) B minus 2 and 1 / 4 minus 20 / 29 times root sign 3 equals 0
Please answer before this Friday!

One third of a should be expressed as "A / 3"; the root of two thirds of a should be expressed as "√ 3 / 2 * a"
(A / 3 + √ 3 / 2 * a) + (1 / 4 - √ 3 / 12) * B-2 and 1 / 4-29 / 20 * √ 3 = 0
(1/3+√3/2)a+(3-√3)/12*b=9/4+29/20*√3
(2+3√3)/6*a+(3-√3)/12*b=9/4+29/20*√3
That is, when (2 + 3 √ 3) / 6 * a = 9 / 4; (3 - √ 3) / 12 * b = 29 / 20 * √ 3,
a=9/4*6/(2+3√3) b=29√3/20*12/(3-√3)
=27/2*(2-3√3)/(4-27) =87√3/[5(3-√3)
=-27/46*(2-3√3) =87/30*√3*(3+√3)
=87√3/10+87/10
When (2 + 3 √ 3) / 6 * a = 29 / 20 * √ 3; (3 - √ 3) / 12 * b = 9 / 4,
a=(29/20*√3)*6/(2+3√3) b=9/4*12/(3-√3)
=-29*6√3*(2-3√3)/(20*23) =27/(3-√3)
=-87/230*(2√3-3) =4.5(3+√3) .

Given the square of the root sign (x-1000) + (root sign 998-x) = 2000, y = root sign m + 8 + root sign M-1 + root sign 1-m, find the square root of y-x,

From the meaning of √ (998-x), we can see that:
X≤998,
∴|X-1000|+998-X=2000
1000-X+998-X=2000
X=-1,
From the meaning of √ (m-1) and √ (1-m), it is concluded that:
m=1,
∴Y=√(m+8)=3,
∴Y-X=3-(-1)=4.

Given 3x = 108, y = 1000, find the arithmetic square root of X + y

3x equals 108, x = 36, y = 1000, the arithmetic square root of X is 6, the arithmetic square root of Y is 10 * root sign 10

Please give me a question about the application of fractional equation in the second semester of junior high school mathematics

Some people are going to buy a box of cigarettes together. Later, considering that smoking pollutes the environment, 15 people are not allowed to smoke, and the rest have to share 15 yuan more. When they decide to pay, another 5 people will not buy, and finally the rest will increase 10 yuan more

A. The distance between two places is 60km. A starts from place a to place B by bicycle. One hour after starting, B goes from place a to place B by motorcycle, and B arrives 3 hours earlier than A. It is known that the speed of B is 3 times that of A. the speed of a and B should be calculated

Suppose the speed of a is XKM / h, then the speed of B is 3xkm / h. according to the meaning of the question, there is 60x = 603x + 4. Solve this equation and get x = 10. After testing, x = 10 is the solution of the original equation. When x = 10, 3x = 30. A: the speed of a is 10km / h, and the speed of B is 30km / h