The least common multiple of 9 and 51 How much is it?

The least common multiple of 9 and 51 How much is it?


153, absolutely



What is the least common multiple of 52 and 21?


Because there is no common factor, it can only be multiplied



Least common multiple of 52 and 28
vxgvfgfnfg


The least common multiple of 52 and 28 -- 364
52×7=364
28×13=364



Given the numbers 3 and 12, please give another number so that one of the three numbers is the square root of the product of the other


6 or 48 is OK. If you don't specify the number, then 3 / 4 is OK
3 * 12 = 36, the square root is 6
12^2=144= (3*a)^2 ===> a=48
3^2=9= (12*a)^2 ===> a=3/4



(x + 1) square - (x + 2) * (X-2) where the square root of 5 is less than the square root of X less than 10 and X is an integer


3>√5>2
4>√10>3
Square root of 5 < square root of X < 10
And because x is an integer
So x can only be 3
(x + 1) square - (x + 2) * (X-2)
=x²+2x+1-(x²-4)
=x²+2x+1-x²+4
=2x+5
=2×3+5
=11



The binomial expansion of [X-2 / square root of x] ^ 5, the coefficient of x ^ 2 is ()


Binomial expansion of [square root of X-2 / x] ^ 5
T (R + 1) = C (5, R) * x ^ (5-r) * - 2) ^ R * x ^ (- R / 2) = - 2) ^ R * C (5, R) * x ^ (5-3r / 2)
∴ 5-3r/2=2
∴ r=2
That is to say, the term containing X & # is the third term,
The coefficient is (- 2) ^ 2 * C (5,2) = 4 * 10 = 40



1. There are several integers satisfying √ X-2 - √ X-8. 2. Given that (1 + √ 2) ^ 2 = 3 + 2 √ 2, then the number 1 smaller than the square root of (3 + 2 √ 2) is
3. Given that the square roots of a number are a + B-2 and B + 3, the arithmetic square root of 4A + 3B + 3 is 3, find the square root of 3A + 3B
Ask for explanation


1. There are seven integers satisfying √ X-2 - √ X-8, namely 2,3,4,5,6,7,8. 2. Given that (1 + √ 2) ^ 2 = 3 + 2 √ 2, then the number 1 smaller than the square root of (3 + 2 √ 2) is 1 + radical 2-1 = radical 2, or - (1 + radical 2) - 1 = - 2 - radical 2, because there are two square roots of a positive number, and these two numbers are opposite numbers 3



If M + 1 and M + 3 are the square roots of a number x, find the values of M and X


If M + 1 and M + 3 are the square roots of a number X
Then M + 1 + m + 3 = 0
So m = - 3 / 2
So x = (M + 1) ^ 2 = (- 3 / 2 + 1) ^ 2 = 1 / 4
If you don't understand, please ask, I wish you a happy study!



The absolute value of the square root of X-2 + 2Y + 6


∵ radical X-2 + / 2Y + 6 / = 0
∴x-2=0 2y+6=0
∴x=2,y=-3



Find the range y = x & # 178; - 4x + 6 x ∈ [0,3]


y=x²-4x+6
=(x-2)^2+2
The axis of symmetry x = 2 is in the interval [0,3]
Obviously when 0