Given - 3 ∈ {A-3, 2a-1, A2 + 1}, find the value of real number a

Given - 3 ∈ {A-3, 2a-1, A2 + 1}, find the value of real number a

∵ - 3 ∈ {A-3, 2a-1, A2 + 1}, and A2 + 1 ≥ 1, ∵ - 3 = A-3, or - 3 = 2a-1, the solution is a = 0, or a = - 1, when a = 0, {A-3, 2a-1, A2 + 1} = {- 3, - 1, 1}, satisfying the three elements of the set; when a = - 1, {A-3, 2a-1, A2 + 1} = {- 4, - 3, 2}, satisfying the three elements of the set; ∵ a = 0 or - 1; when a = - 1, {A-3, 2a-1, A2 + 1} = {4, - 3, 2}, satisfying the three elements of the set; when a = -;

If the square of X is greater than or equal to the x power of 2 (x is greater than or equal to 0), find the value range of X

4≥x≥2

The second power of [X-2] is equal to one, and the value range of X is

3 or 1

C language algorithm, judge a number is a prime number? To program

/*To judge whether a number 'n' is prime number or not*/#include#includeint main(){int n,i,k,prime=1;do{printf("Please input a positive number:\nn=");scanf("%d",&n);}while(n

Algorithm to determine whether a number is prime, flow chart

There are two algorithms
1. Enter a number n
flag=0;
for(int i=2;i

A method of judging prime number by C #
public class Primes
{
private long min;
private long max;
Public primes(): this (2100) / / why is this (2100)? What is the function of this?
{
}
public Primes(long minimum,long maximum)
{
if (min < 2)
min = 2;
else
min = minimum;
max = maximum;
}
public IEnumerator GetEnumerator()
{
for (long possiblePrime = min; possiblePrime

Public primes(): this (2, 100) / / is an overload of its own constructor {} / / that is, public primes (long minimum, long maximum) {if (min < 2) mi

An algorithm for judging whether a number a is prime or not
The most important thing is to find the algorithm for at least how many times of division operation, that is, the judgment algorithm for the least number of times of operation. It can be programmed with C + +
In fact, there is also an algorithm with the least number of runs, that is, to judge whether for (int i = 2; I * I)

int sushu(int N)
{
int i;
int flag=1;
If (n = = 1) return false; / / 1 is neither prime nor prime
if (N==2) return true;
for (i=2;i

Find the sum of all prime numbers within 100, count the number of prime numbers and output each prime number (5 per line) in C language program (c + +)
Help with basic sentences

The complexity of the above two digits is a little high. To be simple, remove the multiples of 2, 3, 5 and 7 within 100 (except 2), that is, all prime numbers
#include
#include
using namespace std;
int main(){
int i,j,sum=0,k=0;
bool flag=true;
for(i=2;i

The sum of three times of a prime number and two times of another prime number is 100. What is the sum of the two prime numbers?

49
Let XY, 2x + 3Y = 100
Y is even, otherwise x cannot be selected
And because y is a prime number, it is 2
Then x is 47
So 49

3. Help to prove that root 3 is irrational 4. Prove that there are infinite prime numbers

According to Pythagoras, any number can be expressed as a fraction or an integer, but until someone (eudox) pointed out: how to express the diagonal length of a unit square? It has seriously damaged Pythagoras's belief. Now let's hit him again^_ ^Suppose there is such a rational number P, P ^ 2 = 2